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3 years ago

IF UR SMART U SHOULD KNOW THIS PLEASE HELP 10 POINTS

Mathematics

1 answer:

stellarik [79]3 years ago

7 0

They're all simple.

150 = 25r

The r is multiplied for 25, so we should know what r equals to when it's not multiplied (1r).

So divide both terms for 25.

150/25 = 25r/25

6 = r

r = 6 <- answer

38 = 4p

Same thing here (divide both terms for 4)

38/4 = 4p/4

38/4 = p

p = 38/4 and simplify p = 19/2 <- answer

18 = a/20

We have a fraction, and we have to "delete" it.

There are two ways.

First one: multiply both terms for the denominator of the fraction.

18*20 = a/20 * 20

360 = a

a = 360 <- answer

Second way.

Take the two fractions to the common denominator (20) and do the LCM.

360/20 = a/20. Multiply both for 20

360 = a

a = 360

0 = 10x

0/10 = 10x/10

x = 0 <- answer

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Answer: Choice A

Note: the range should be $[-5, \infty)$ . See explanation below.

===================================================

We can plug in any real number for x to get some output for y. The domain is the set of all real numbers in which we say $(-\infty, \infty)$ which is interval notation. It represents the interval from negative infinity to positive infinity.

The range is the set of possible outputs. The smallest output possible is y = -5 which occurs at the vertex (3,-5). We can get this y value or larger. So we can describe the range as the set of y values such that $y \ge -5$ and that translates to the interval notation $[-5, \infty)$ .

The square bracket says "include this endpoint" while the curved parenthesis says to exclude the endpoint. Your teacher mistakenly wrote $(-5, \infty)$ for choice A, when they should have written $[-5, \infty)$

I think either your teacher made a typo or somehow the formatting messed up. Either way, choice A is the closest to the answer.

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3 years ago

Read 2 more answers

Enter your answer

satela [25.4K]

Answer:So, since it is continuously, we need to think of PERT

A=P\times e^{rt}

So, we just plug our numbers in to solve for T

8000=4000e^{.07t}\\\ln(8000)=\ln(4000e^{.07t})\\\ln(8000) = \ln(4000) + \ln(e^{.07t})\\\ln(8000)=\ln(4000)+.07t\ln(e)\\\ln(8000)=\ln(4000)+.07t\\\frac{\ln(8000)}{\ln(4000)}=.07t\\\frac{\ln(8000)}{.07\ln(4000)}=t\\ 15.479=t

It will take 15.479 years

Step-by-step explanation:

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3 years ago