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Dima020 [189]
2 years ago
7

Compare by using < > or = between the pairs of numbers l - 8l ____ l2l

Mathematics
1 answer:
valentina_108 [34]2 years ago
8 0

Answer:

It is >

Step-by-step explanation:

because the absolute value of -8 is 8 and the absolute value of 2 is 2 so 8 is bigger than 2

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Bob and Mark talk about their families. Bob says he has 3 kids, the product of their ages is 72. He gives another clue: the sum
Damm [24]
Not this riddle again


3 kids
what you are supposed to do is factor 72 and see their sums
1+1+72=74
1+2+36=39
1+3+24=28
1+4+18=23
2+2+18=22
1+6+12=19
2+3+12=17
1+8+9=18
2+4+9=15
2+6+6=14
3+3+8=14
3+4+6=13


notice that all the sums are different except for the 2 that add to 14
since there is not enough info, we can conclude that the sum was 14 and that the ages is either 2,6,6 or 3,3,8
after he says, "the youngest is called justice"
now we know there is a youngest
it cannot be 3,3,8 because 3 and 3 are both youngest
therefor the ages are
2,6 and 6 years old
7 0
3 years ago
Pls picture is very easy help pls
Ira Lisetskai [31]
Where is the pic sir?
6 0
2 years ago
Somebody please help me help me on this it’s GEOMETRY it is URGENT please DO NOT waste my answers
Norma-Jean [14]

Answer:

∠G ≅ ∠Q

Step-by-step explanation:

<u>Given</u>

  • ΔBIG ≅ ΔPQZ

<u>Answer choices:</u>

  • BI≅PQ - yes correct, corresponding
  • ∠B ≅ ∠P - yes correct, corresponding
  • ∠G ≅ ∠Q - no, incorrect, it should read ∠G ≅ ∠Z
  • ZP ≅ GB -  yes correct, corresponding

So, incorrect choice is the third one

8 0
3 years ago
A certain circle can be represented by the following equation. x^2+y^2+6y-72=0 What is the center of this circle ?
jek_recluse [69]

Answer:

(0, -3)

Step-by-step explanation:

Here we'll rewrite x^2+y^2+6y-72=0 using "completing the square."

Rearranging x^2+y^2+6y-72=0, we get  x^2 + y^2 + 6y                = 72.

x^2 is already a perfect square.  Focus on rewriting y^2 + 6y as the square of a binomial:  y^2 + 6y becomes a perfect square if we add 9 and then subtract 9:

x^2 + y^2 + 6y + 9  - 9              = 72:

x^2 + (y + 3)^2 = 81

Comparing this to the standard equation of a circle with center at (h, k) and radius r,

(x - h)^2 + (y - k)^2 = r^2.  Then h = 0, k = -3 and r = 9.

The center of the circle is (h, k), or (0, -3).

8 0
3 years ago
Math problem.. 16 points and brainly very easy problem
Leni [432]

Answer:

can you type it so i can answer it, i cant see the picture

Step-by-step explanation:

6 0
2 years ago
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