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xeze [42]
3 years ago
6

The corresponding sides of two similar rectangles are 6 ft and 10 ft. The area of the smaller rectangle is 78 ft2. To the neares

t whole number, what is the area of the larger rectangle?
Mathematics
1 answer:
Ira Lisetskai [31]3 years ago
3 0
We know one side of the smaller rectangle, 6ft. Therefore the longer side is 78/6 ft = 13ft.

The ratio of small to large side is 6:10, so the larger rectangles other length is (13 / 6) * 10 ft = 21.666... ft.

Thus the area of the larger rectangle is 21.666... * 10 = 216.666... ft^2, and hence to the nearest whole number it is 217 ft^2
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Which of these is an equivalent expression for x-3 that uses positive exponents?
nignag [31]
Wait are you going to send a picture to fully show us what the question is about
5 0
3 years ago
Read 2 more answers
The county fair charges $1.25 per ticket for the rides. Jermaine bought 25 tickets for the rides and spent a total of $43.75 at
Aleksandr-060686 [28]

A.)y=1.25x+12.5

B.)ridecost+admission=total

if x=number of tickets and y is total and cost per ride is 1.25,

1.25x+admission=y

when we solve

when x=25, y=43.75

Hope This Helps!!!

-Austint1414

5 0
3 years ago
Read 2 more answers
Someone please help me with this lol… have no idea what I’m doing
Sholpan [36]

Given:

\cos \theta =\dfrac{3}{5}

\sin \theta

To find:

The quadrant of the terminal side of \theta and find the value of \sin\theta.

Solution:

We know that,

In Quadrant I, all trigonometric ratios are positive.

In Quadrant II: Only sin and cosec are positive.

In Quadrant III: Only tan and cot are positive.

In Quadrant IV: Only cos and sec are positive.

It is given that,

\cos \theta =\dfrac{3}{5}

\sin \theta

Here cos is positive and sine is negative. So, \theta must be lies in Quadrant IV.

We know that,

\sin^2\theta +\cos^2\theta =1

\sin^2\theta=1-\cos^2\theta

\sin \theta=\pm \sqrt{1-\cos^2\theta}

It is only negative because \theta lies in Quadrant IV. So,

\sin \theta=-\sqrt{1-\cos^2\theta}

After substituting \cos \theta =\dfrac{3}{5}, we get

\sin \theta=-\sqrt{1-(\dfrac{3}{5})^2}

\sin \theta=-\sqrt{1-\dfrac{9}{25}}

\sin \theta=-\sqrt{\dfrac{25-9}{25}}

\sin \theta=-\sqrt{\dfrac{16}{25}}

\sin \theta=-\dfrac{4}{5}

Therefore, the correct option is B.

6 0
2 years ago
You take a 200 milligram dosage of aspirin. During each subsequent hour, the amount of medication in your bloodstream decreases
shepuryov [24]

Answer: The level of aspirin (mg) will be in your bloodstream in 4 hours = 35.70 mg.

Step-by-step explanation:

If the amount is decreasing by r%, then the final amount is given by :-

A=P(1-r)^t

, where P = initial value , t= time

Given: P= 200 milligram, r= 35% = 0.35, t= 4 hours

The level of aspirin (mg) will be in your bloodstream in 4 hours = 200(1-0.35)^4

=200(0.65)^4\\\\=200\times 0.17850625\\\\=35.70125\approx35.70 \ mg

Hence, the level of aspirin (mg) will be in your bloodstream in 4 hours = 35.70 mg.

5 0
2 years ago
Suppose that the radius of a circle increases at a constant rate of 0.25 cm/sec. When the radius of this circle is 16 cm, the ar
irakobra [83]

Answer:

8πcm²/sec

Step-by-step explanation:

The radius of the circle increases at a rate of dr/dt = 0.25cm/sec

The radius of the circle r = 16cm

The area of the circle increases at a rate of dA/dt = ?

Area of a circle = πr²

We take the derivative with respect to t

dA/dt = 2πrdr/dt

dA/dt = 2 π (16)(0.25)

dA/dt = 8πcm²/sec

Thank you!!!

5 0
3 years ago
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