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zavuch27 [327]
3 years ago
5

Simplify the expression (6^2)^4.

Mathematics
2 answers:
Klio2033 [76]3 years ago
8 0

Answer:

1679616

17 (simplified)

Step-by-step explanation:

Apply the exponent rule (what exponents do)

(6^2)^4 = 6^2*4

= 6^2*4

Multiply the numbers: 2*4=8

=6^8

6^8 = 1679616

Vlada [557]3 years ago
7 0

Answer:

1679616

Step-by-step explanation:

36^4

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190 = 200^b, make b the subject​
MArishka [77]

Answer:

b = \frac{ln190}{ln200}

Step-by-step explanation:

Using the rule of logarithms

log x^{n} ⇔ nlogx

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3 0
3 years ago
A tank contains 1000 L of pure water. Brine that contains 0.05 kg of salt per liter of water enters the tank at a rate of 5 L/mi
Margaret [11]

Answer:

a) y(t)=0.65\frac{Kg}{min}(tmin)

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Step-by-step explanation:

Data

Brine a (Ba)

V_{Ba}=5\frac{Lt}{min}\\  Concentration(Bca)=0.05\frac{Kg}{Lt}

Brine b (Bb)

V_{Bb}=10\frac{Lt}{min}\\  Concentration(Bcb)=0.04\frac{Kg}{Lt}

we have that per every minute the amount of solution that enters the tank is the same as the one that leaves the tank (15 Lt / min)

, then the amount of salt (y) left in the tank after (t) minutes: y=V_{Ba}*B_{ca}+V_{Bb}*B_{cb}=5\frac{Lt}{min}*0.05\frac{Kg}{Lt}+10\frac{Lt}{min}*0.04\frac{Kg}{Lt}=\\0.25\frac{Kg}{min}+0.4\frac{Kg}{min}=0.65\frac{Kg}{min}

Finally:

a) y(t)=0.65\frac{Kg}{min}(tmin)

b) y(40)=0.65\frac{Kg}{min}(40min)=26Kg

being y(t) the amount of salt (y) per unit of time (t)

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Colt1911 [192]

Answer:

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Step-by-step explanation:

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