3 years ago

What is an equation of a line that passes through the points (-4,8) and (2,-1)?

Mathematics

1 answer:

Evgesh-ka [11]3 years ago

3 0

Answer:

y = 3/2x + 20

Step-by-step explanation:

Use point-slope form. (long to explain, it is correct though).

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(3ab+2c)^3 what is the answer

svet-max [94.6K]

Answer:

$=27a^3b^3+54a^2b^2c+36abc^2+8c^3$

Step-by-step explanation:

$(3ab+2c)^3$

$=(3ab+2c)$ × $(3ab+2c)$ ×

$=(3ab+2c)(9a^2b^2+12abc+4c^2)$

$=(3ab)(9a^2b^2)+(3ab)(12abc)+(3ab)(4c^2)+(2c)(9a^2b^2)+(2c)(12abc)+(2c)(4c^2)$

$=27a^3b^3+36a^2b^2c+12abc^2+18a^2b^2c+24abc^2+8c^3$

$=27a^3b^3+54a^2b^2c+36abc^2+8c^3$

<em>hope this helps....</em>

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3 years ago

Direct Variation.<br>¯\_(ツ)_/¯

Alekssandra [29.7K]

Answer:

y = 1/6

Step-by-step explanation:

direct variation

y =kx

substitute in what we know to find k

1/2 = k*3

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divide by 3

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substitute k into the direct variation equation

y = 1/6 x

let x = 1

y = 1/6 *1

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Step-by-step explanation:

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