2 years ago

If EF bisects CD, CG =5x-1, GD = 7x-13, EF = 6x-4, and GF =13, find EG

1 answer:

6 0

Greetings from Brasil....

As stated in the statement of the question, EF is a bisector of CD, so point G is the median point of CD, so CG = GD

5X - 1 = 7X - 13

X = 6

EF = EG + GF

6X - 4 = EG + 13 x = 6, so

6·6 - 4 = EG + 13

(see attachment)

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