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Arte-miy333 [17]
3 years ago
5

Evaluate the expression when d=-3 |d|

Mathematics
1 answer:
nirvana33 [79]3 years ago
8 0
Alright. Start by plugging in -3 for d. There are absolute value signs on the outside, so it negates the negative and makes it just 3. I hope this helps you. 

From, 
Am3865211
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An equation is shown below: 2(3x − 5) = 1 Which of the following correctly shows the first two steps to solve this equation? Ste
Crazy boy [7]

Answer:

A: Step 1: 6x − 10 = 1; Step 2: 6x = 11

Step-by-step explanation:

First: remove parentheses by multiplying factors.

6x - 10 = 1

Second: Move the constants to the right side of the equation

6x = 1 + 10

6x = 11

5 0
3 years ago
Read 2 more answers
A carpenter needs to cut four sections, each 3–feet 8–inches long, from a piece of molding. If the board is only sold by the foo
Volgvan

3 feet 8 inches converted to inches is 3x12+8=44inches

44inches times 4 pieces is 176 inches.

176 inches converted back to feet and inches is 176/12=14 feet 8 inches so he would need 15 feet of board

3 0
3 years ago
What is the solution ? Please help with this !!
FromTheMoon [43]

Answer:

the answer is c

Step-by-step explanation:

see picture

7 0
2 years ago
Please, someone, help me ASAP
ryzh [129]
1.) Beachy-Keen
2.) shorething
3.) shorething
4.) Beachy-Keen
5.) shorething

let me know if you think any of these are incorrect hope it helps
4 0
3 years ago
Three consecutive vertices of a parallelogram are (– 2, 1); (1, 0) and (4, 3). Find the coordinate of the fourth vertex and find
antiseptic1488 [7]

Answer:

D(1,4) - the fourth vertex, the area is equal to 12

Step-by-step explanation:

A(2,-1), B(1,0),C(4,3), They are consecutive, we need to find the point D, find the midpoint of AC (O)

xo= (xA+xc)/2    x0= (-2+4)/2=1

y0=(yA+yC)/2    y0= (1+3)/2=2

0(1,2)

O is the midpoint of BD, so let's find the vertex D

X0= (xB+xD)/2     1= (1+xD)/2   xD=1

y0= (yB+yD)/2      2= (0+yD)/2    yD=4

D(1,4)

the vector DA is (-2-1, 1-4)= (-3,-3)

the vector DC is (4-1, 3-4)= (3,-1)

The modul of DC is sqrt ((-3)^2+(-3)^2)= 3*sqrt2(the length of the side Dc)

The modul of DA is sqrt (3^2+(-1)^2)= sqrt10(the length of the side DA)

cosD= (-3*3+(-3)(-1))/3*sqrt2*sqrt10=-6/3*2*sqrt5=-1/sqrt5

sinD= sqrt (1- 1/5)=2/ sqrt5

S=3sqrt2*sqrt10*2/sqrt5= 12

6 0
2 years ago
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