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vesna_86 [32]
3 years ago
5

(c) Do we need both rates? In real life, when will each rate become useful?

Mathematics
1 answer:
abruzzese [7]3 years ago
6 0
What do you mean by “rates” ?
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The function h(t) = -4.9t2 + h0 gives the height (h), in meters, of an object t seconds after it falls from an initial height (h
sveticcg [70]
It will hit the ground after 3.499 seconds.

To solve this you first have to find the value of h(0) in this equation. That is the height from which it was dropped.

You can input any of the points into the equation and solve for the missing part. You will get 60 for the height.

The use the quadratic formula to see that it reaches the ground after 3.499 seconds.
7 0
3 years ago
Read 2 more answers
F(x) = 3x3 – 2x2 + x - 4 at x = -3
Yuri [45]

Steps to solve:

f(x) = 3x³ – 2x² + x; x = -3

~Substitute

f(-3) = 3(-3)³ - 2(-3)² + (-3)

~Solve the exponents

f(-3) = 3(-27) - 2(9) + (-3)

~Multiply

f(-3) = -81 - 18 - 3

~Subtract

f(-3) = -102

Best of Luck!

5 0
4 years ago
A brick of cheese is 3/4 inch thick . A deli cuts the brick of cheese into slices that are 1/8 thick. How many 1/8 inch slices c
Vesnalui [34]
3/4 is the simplified version of 6/8. How I got this is I know that 4 goes into 8 twice so you multiply by 2. Whatever you do to the bottom you do to the top so you will get 6/8.
8 0
3 years ago
Workout the length of AB. Give your answers to 3 significant figures.
german

Answer:

AB ≈ 6.71

Step-by-step explanation:

Calculate the length using the distance formula

d = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2    }

with (x₁, y₁ ) = A (- 1, 6) and (x₂, y₂ ) = B (5, 3)

AB = \sqrt{(5-(-1))^2+(3-6)^2}

    = \sqrt{(5+1)^2+(-3)^2}

    = \sqrt{6^2+9}

    = \sqrt{36+9}

    = \sqrt{45}

    ≈ 6.71 ( to 3 significant figures )

8 0
3 years ago
Please help it’s geometry will mark brainliest!
Dima020 [189]

Answer:

its 216

Step-by-step explanation:

when it's one the edge the arc is double the angle

5 0
3 years ago
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