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vesna_86 [32]
3 years ago
5

(c) Do we need both rates? In real life, when will each rate become useful?

Mathematics
1 answer:
abruzzese [7]3 years ago
6 0
What do you mean by “rates” ?
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2 years ago
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Anyone can help me solve this equation using cross multiplying
Natali5045456 [20]

9514 1404 393

Answer:

  x = 1 or 5

Step-by-step explanation:

The notion of "cross-multiplying" is the idea that the numerator on the left is multiplied by the denominator on the right, and the numerator on the right is multiplied by the denominator on the left. This looks like ...

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\ \longrightarrow\ (x-1)(3x-1)=(7)(2x-2)

Then the solution proceeds by eliminating parentheses, and solving the resulting quadratic equation.

  3x^2-4x+1=14x-14\\\\3x^2-18x+15=0\qquad\text{subtract $14x-14$}\\\\x^2-6x+5=0 \qquad\text{divide by 3}\\\\(x-1)(x-5)=0\qquad\text{factor}\\\\x\in\{1,5\}

_____

<em>Comment on "cross multiply"</em>

Like a lot of instructions in Algebra courses, the idea of "cross multiply" describes <em>what the result looks like</em>. It doesn't adequately describe how you get there. The <em>one and only rule</em> in solving Algebra problems is "<em>whatever is done to one side of the equation must also be done to the other side of the equation</em>." If you multiply one side by one thing and the other side by a different thing, you are violating this rule.

What looks like "cross multiply" is really "<em>multiply by the product of the denominators</em> and cancel like terms from numerator and denominator." Here's what that looks like with the intermediate steps added.

  \displaystyle \frac{x-1}{7}=\frac{2x-2}{3x-1}\\\\\frac{x-1}{7}\times7(3x-1)=\frac{2x-2}{3x-1}\times7(3x-1)\\\\(x-1)(3x-1)=(2x-2)(7)\qquad\textit{looks like}\text{ cross multiply}

8 0
2 years ago
Determine if the leading coefficient of the following function is positive or negative and whether the function has a minimum or
fenix001 [56]

Answer:

The function has a negative leading coefficient and a maximum vertex point

Explanation:

This function's leading coefficient is determined by whether it is concave up or concave down, meaning it has an Up and Up end behavior for a positive leading coefficient and a Down and Down end behavior for a negative coefficient.

This function's end behavior is Down and Down, so it must have a negative leading coefficient.

The function has a minimum vertex when the function has a positive leading coefficient and a maximum vertex point when the function has a negative leading coefficient.

This means that the functions vertex is the highest or lowest possible value of the function (the rest of the function continues forever in whichever direction.

This particular function has a maximum vertex as there is no point above the vertex here and the function has a negative leading coefficient.

4 0
3 years ago
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Simplify 3(tan^2 theta - sec^2 theta)<br> a. 1<br> b. 0<br> c. -3<br> d. 3<br><br> *ITS NOT D*
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Answer:

it's option c. - 3

Hope it will help :)❤

4 0
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emmasim [6.3K]

Answer: I'm guessing it's acute

Step-by-step explanation:

Since all the angles are less that 90 degrees, it can't be right or obtuse. I'm gonna say acute

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