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3 years ago

the lengths of two sides of a triangle are 15 and 13. find the lengths that the third side must be greater and less then.

Mathematics

1 answer:

SCORPION-xisa [38]3 years ago

5 0

Answer:

greater than 2

less than 28

Step-by-step explanation:

The sum of the lengths of the two shortest sides must be more than the length of the longest side. If x is the shortest side, ...

... x + 13 > 15

... x > 2

If x is the longest side, ...

... 13 +15 > x

... x < 28

Then the allowed range for the third side is ...

... 2 < x < 28

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Put the numbers in order from least to greatest.

koban [17]

Answer:

$0.5\times{10}^{-5}$ ,

0.00025,

$3.5\times{10}^{-4}$ ,

$1.45 \times {10}^{-3}$ ,

$25.4 \times {10}^{ - 4}$ ,

0.025,

$1.25\times {10}^{-1}$ ,

$0.025 \times10$

Step-by-step explanation:

We can do it this way.

First, let us clear off the powers by multipying each number by

${10}^{5}$

This implies that,

$1.25 \times {10}^{ - 1} = 1.25 \times {10}^{ - 1} \times {10}^{5}$

$\implies \: 1.25 \times {10}^{ - 1} = 125 \times {10}^{ - 2} \times {10}^{ - 1} \times {10}^{5}$

$\implies \: 1.25 \times {10}^{ - 1} =125 \times {10}^{( - 2 - 1 + 5)}$

$\implies \: 1.25 \times {10}^{ - 1} =125 \times {10}^{2}= 125 \times 100 = 12500$

$0.00025 = 25 \times {10}^{ - 5} \times {10}^{5}$

$\implies0.00025 = 25 \times {10}^{ - 5 + 5} = 25$

$0.025 = 25 \times {10}^{ - 3}=25 \times{10}^{ - 3}\times {10}^{5}$

$\implies0.025 = 25 \times {10}^{ - 3}=25 \times{10}^{ - 3 + 5}$

$\implies0.025 = 25 \times {10}^{ - 3}=25 \times{10}^{2} = 25 \times 100 = 2500$

$0.025 \times 10=25 \times {10}^{ - 3} \times10 \times {10}^{5}$

$\implies0.025 \times10=25\times{10}^{(- 3 + 1 + 5)}=25\times{10}^{3}$

$\implies0.025\times10=25\times1000 = 25000$

$0.5\times {10}^{-5}=0.5\times {10}^{ - 5} \times {10}^{5}$

$0.5\times{10}^{-5}=0.5\times {10}^{(- 5+5)}=0.5$

$1.45 \times {10}^{-3} = 145 \times {10}^{ - 2} \times {10}^{ - 3} \times {10}^{5}$

$\implies1.45 \times {10}^{-3} = 145$

$25.4 \times {10}^{ - 4} = 254 \times {10}^{-1} \times {10}^{ - 4} \times {10}^{5}$

$\implies25.4 \times {10}^ {-4} = 254$

$3.5 \times{10}^{-4}=35 \times {10}^{-1} \times {10}^{ - 4} \times {10}^{5}$

$\implies3.5 \times{10}^{-4}=35$

Arranging in order from the smallest, we have;

0.5,25,35,145,254,2500,12500,25000

Hence,

$0.5\times{10}^{-5}$ ,

0.00025,

$3.5\times{10}^{-4}$ ,

$1.45 \times {10}^{-3}$ ,

$25.4 \times {10}^{ - 4}$ ,

0.025,

$1.25\times {10}^{-1}$ ,

$0.025 \times10$

5 0

2 years ago

What is the solution to the equation below?

Bess [88]

W=2/12 you just divide both sides by 4

5 0

2 years ago

PLS HELP!!! I DONT GET THIS

Serhud [2]

Answer:

73 2/6

Step-by-step explanation:

5 0

2 years ago

Round to the nearest thousandth 1.0835

jek_recluse [69]

Answer:

1.084

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Round to nearest tenth and solve for x

stepladder [879]

Answer:

$\displaystyle 9,6$

Step-by-step explanation:

$\displaystyle \frac{x}{6,4} = csc\:42 \hookrightarrow 6,4cot\:42 = x \hookrightarrow 9,5646499191... = x \\ \\ 9,6 ≈ x$

$\displaystyle \frac{6,4}{x} = sin\:42 \hookrightarrow xsin\:42 = 6,4 \hookrightarrow \frac{6,4}{sin\:42} = x \hookrightarrow 9,5646499191... = x \\ \\ 9,6 ≈ x$

Information on trigonometric ratios

$\displaystyle \frac{OPPOCITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOCITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOCITE} = csc\:θ \\ \frac{ADJACENT}{OPPOCITE} = cot\:θ$

I am joyous to assist you at any time.

6 0

1 year ago