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4 years ago

Rewrite the expressions below as the sum of one

1 answer:

8 0

I'll try this again.

<span>2(x - 4) + 6x - 5x * 3
2x - 8 + 6x - 15x Distributed and then multiplied 5x and 3
-7x - 8 after collecting like terms (2x + 6x - 15x) </span>

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What value of c makes the equation true? (problem shown in the picture provided)

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3 years ago

Find the inverse of y=0.3x

Anastaziya [24]

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Step-by-step explanation:

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Which equation can be used to find 40% of 25

guapka [62]

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4 years ago

WHAT IS THE SLOPE IF I HAVE (-3,5) AND (4,-5)

irina [24]

Answer:

-10/7

Step-by-step explanation:

Use slope formula

$\frac{y2-y1} {x2-x1}$

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3 years ago

Please help me do it

Lana71 [14]

Step-by-step Explanation:

We are going to solve this problem using integration by parts. We can write the integrand as

$\dfrac{4x}{x^2+4x+3} = \dfrac{4x}{(x+3)(x+1)}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:= \dfrac{A}{x+3} + \dfrac{B}{x+1}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:= \dfrac{Ax + A + Bx + 3B}{x^2+4x+3}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:=\dfrac{(A+B)x + (A+3B)}{x^2+4x+3}$

Comparing the above term to the left hand side, we can see that

(A + B)x = 4x

A + 3B = 0

Solving for A and B, we find that A = 6 and B = -2 so our integrand becomes

$\dfrac{4x}{x^2+4x+3} = \dfrac{6}{x+3} - \dfrac{2}{x+1}$

We can now easily integrate this expression as follows:

$\displaystyle \int{\dfrac{4x}{x^2+4x+3}}dx = 6\int{\dfrac{dx}{x+3}} - 2\int{\dfrac{dx}{x+1}}$

$\:\:\:\:\:\:\:\:\:\:\:\:\:= 6\ln|x+3| - 2\ln|x+1| + C$

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2 years ago