Can you guys. help me up pliz
2 answers:
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Hello,
Let's x² the square number
and 3*y the multiple of 3.
2 solutions : for (x,y) as integers : (-6,18) and (6,18)
but one solution for (x²,3y) as integers :<u> (36,54) </u>
Answer:
Mean = 35
Variance = 291.7
Step-by-step explanation:
Data provided in the question:
X : 1, 2, 3, 4, 5, 6
All the data are independent
Thus,
The mean for this case will be given as:
Mean, E[X] =
or
E[X] =
or
E[X] = 3.5
For 10 days, Mean = 3.5 × 10 = 35
And,
variance = E[X²] - ( E[X] )²
Now, for this case of independent value,
E[X²] =
or
E[X²] =
or
E[X²] =
or
E[X²] = 15.167
Therefore,
variance = E[X²] - ( E[X] )²
or
variance = 15.167 - 3.5²
or
Variance = 2.917
For 10 days = Variance × Days²
= 2.917 × 10²
= 291.7