Answer:
1728000
Step-by-step explanation:
You always work from the parenthesis first because of order of operation. You have 12( because 2 times 6) then mulitply 12 times 10. You get 120 then you multiply it but itself 3 times. 120 x 120 x 120= 1728000
Answer:

Step-by-step explanation:
The graph you see there is called a parabola. The general equation for the graph is as below

To find the equation we need to find the constants a and b. The constant b is just how much we're lifting the parabola by. Notice it's lifted by 1 on the y axis.
To find a it's a little more tricky. Let's use the graph to find a value for a by plugging in values we know. We know that b is 1 from the previous step, and we know that when x=1, y=3. Let's use that!

Awesome, we've found both values. And we can write the result.

I'll include a plotted graph with our equation just so you can verify it is indeed the same.
Based on the calculations, the measure of angle BDF and CFG are 100° and 38° respectively.
<h3>The condition for two parallel lines.</h3>
In Geometry, two (2) straight lines are considered to be parallel if their slopes are the same (equal) and they have different y-intercepts. This ultimately implies that, two (2) straight lines are parallel under the following conditions:
m₁ = m₂
<u>Note:</u> m is the slope.
<h3>What is the alternate interior angles theorem?</h3>
The alternate interior angles theorem states that when two (2) parallel lines are cut through by a transversal, the alternate interior angles that are formed are congruent.
Based on the alternate interior angles theorem, we can infer and logically deduce the following properties from the diagram (see attachment):
For angle BDF, we have:
<BDF = <BDH + <HDF
<BDF = 38° + 62°
<BDF = 100°.
Since angles BDF and DFC are linear pair, they are supplementary angles. Thus, we have:
∠BDF + <DFC = 180°
<DFC = 180 - ∠BDF
<DFC = 180 - 100
<DFC = 80°.
For angle CFG, we have:
∠DFE + <DFC + <CFG= 180°
<CFG = 180° - ∠DFE - <DFC
<CFG = 180° - 62° - 80°
<CFG = 38°.
Read more on parallel lines here: brainly.com/question/3851016
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Answer:
Δ AXY is not inscribed in circle with center A.
Step-by-step explanation:
Given: A circle with center A
To find: Is Δ AXY inscribed in circle or not
A figure 1 is inscribed in another figure 2 if all vertex of figure 1 is on the boundary of figure 2.
Here figure 1 is Δ AXY with vertices A , X and Y
And figure 2 is Circle.
Clearly from figure, Vertices A , X and Y are not on the arc/boundary of circle.
Therefore, Δ AXY is not inscribed in circle with center A.