9514 1404 393
Answer:
1) f⁻¹(x) = 6 ± 2√(x -1)
3) y = (x +4)² -2
5) y = (x -4)³ -4
Step-by-step explanation:
In general, swap x and y, then solve for y. Quadratics, as in the first problem, do not have an inverse function: the inverse relation is double-valued, unless the domain is restricted. Here, we're just going to consider these to be "solve for ..." problems, without too much concern for domain or range.
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1) x = f(y)
x = (1/4)(y -6)² +1
4(x -1) = (y-6)² . . . . . . subtract 1, multiply by 4
±2√(x -1) = y -6 . . . . square root
y = 6 ± 2√(x -1) . . . . inverse relation
f⁻¹(x) = 6 ± 2√(x -1) . . . . in functional form
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3) x = √(y +2) -4
x +4 = √(y +2) . . . . add 4
(x +4)² = y +2 . . . . square both sides
y = (x +4)² -2 . . . . . subtract 2
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5) x = ∛(y +4) +4
x -4 = ∛(y +4) . . . . . subtract 4
(x -4)³ = y +4 . . . . . cube both sides
y = (x -4)³ -4 . . . . . . subtract 4
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Answer:
![Volume = 3.7\ * 10^2\ L](https://tex.z-dn.net/?f=Volume%20%3D%203.7%5C%20%2A%2010%5E2%5C%20L)
Step-by-step explanation:
Given
![Density = 0.001226 g/mL](https://tex.z-dn.net/?f=Density%20%3D%200.001226%20g%2FmL)
![Mass = 1.0\ lb](https://tex.z-dn.net/?f=Mass%20%3D%201.0%5C%20lb)
Required
Determine the volume of air
Density is calculated using:
![Density = \frac{Mass}{Volume}](https://tex.z-dn.net/?f=Density%20%3D%20%5Cfrac%7BMass%7D%7BVolume%7D)
Substitute values for Density and Mass
![0.001226 g/mL = \frac{1.0\ lb}{Volume}](https://tex.z-dn.net/?f=0.001226%20g%2FmL%20%3D%20%5Cfrac%7B1.0%5C%20lb%7D%7BVolume%7D)
Convert lb to grams
![0.001226 g/mL = \frac{1.0 * 453.592\ g}{Volume}](https://tex.z-dn.net/?f=0.001226%20g%2FmL%20%3D%20%5Cfrac%7B1.0%20%2A%20453.592%5C%20g%7D%7BVolume%7D)
![0.001226 g/mL = \frac{453.592\ g}{Volume}](https://tex.z-dn.net/?f=0.001226%20g%2FmL%20%3D%20%5Cfrac%7B453.592%5C%20g%7D%7BVolume%7D)
Solve for Volume
![Volume = \frac{453.592\ g}{0.001226 g/mL}](https://tex.z-dn.net/?f=Volume%20%3D%20%5Cfrac%7B453.592%5C%20g%7D%7B0.001226%20g%2FmL%7D)
![Volume = 369977.161501\ mL](https://tex.z-dn.net/?f=Volume%20%3D%20369977.161501%5C%20mL)
Convert mL to L
![Volume = 369977.161501\ L * 0.001](https://tex.z-dn.net/?f=Volume%20%3D%20369977.161501%5C%20L%20%2A%200.001)
![Volume = 369.977161501\ L](https://tex.z-dn.net/?f=Volume%20%3D%20369.977161501%5C%20L)
Represent using scientific notation
![Volume = 3.69977161501\ * 10^2\ L](https://tex.z-dn.net/?f=Volume%20%3D%203.69977161501%5C%20%2A%2010%5E2%5C%20L)
Approximate
![Volume = 3.7\ * 10^2\ L](https://tex.z-dn.net/?f=Volume%20%3D%203.7%5C%20%2A%2010%5E2%5C%20L)
(-8)^2
(-8)(-8)
64
Hope this helps!
Answer: i think it is... x = -19