reflection and translation.
Given:
The different transformation in the options.
To find:
The transformation that would result in the perimeter of a triangle being different from the perimeter of its image.
Solution:
In option 1,

It represents reflection across the line y=x.
In option 2,

It represents reflection across the x-axis.
In option 3,

It represents dilation by scale factor 4 and the center of dilation is at origin.
In option 4,

It represents translation 2 units right and 5 units down.
We know that the reflection and translation are rigid transformations, It means the size and shape of the figure remains the same after transformation.
So, the perimeter of the figure and its image are same in the case of reflection and translation.
But dilation is not a rigid transformation. In dilation, the figure is similar to its image. So, the perimeter of the figure and its image are different in the case of dilation.
Therefore, the correct option is 3.
SA = 900cm^2
SA = 6×(s^2), where "s" is one side or edge of each square surface face
900 = 6s^2
150 = s^2



So each side is

The volume (V) of a cube is:
In the image below, I showed my work. What you basically do is find the greatest perfect square in each variable and you pull it out of the radical.
You got to measure the question to get 1 + 2 + 5 + 7 + 68 as you can see the links are different as you can see some of the Lakes or the same if you look at 6 and 3 then you'll know that