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Amiraneli [1.4K]
3 years ago
15

The sum of four consecutive whole numbers is 54, what are the four numbers

Mathematics
1 answer:
anastassius [24]3 years ago
7 0
Let the four consecutive numbers be x, x+1, x+2, and x+3.

The sum of the four numbers is 54, therefore
x + (x+1) + (x+2) + (x+3) = 54
4x + 6 = 54
4x = 54 - 6 = 48
x = 12

Answer:
The four numbers are 12, 13, 14, and 15

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  { 4 }

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First you need to solve the equation. Then you need to write the solutions as a set.

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I like to use a graphing calculator to solve equations involving roots. That helps avoid extraneous solutions. Here, the graph of the left side intersects the graph of the right side at x=4. There is exactly one solution, so the solution set is ...

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Solving this algebraically, you would isolate the radical, then "undo" it by squaring both sides of the equation. Then solve the resulting quadratic. That will have 2 solutions, only one of which will work in the original equation.

  √(5x +16) -2 = 3x -8 . . . . given

  √(5x +16) = 3x -6 . . . . . .  add 2

  5x +16 = (3x -6)^2 . . . . .  square both sides

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  9x^2 -41x +20 = 0 . . . . . . subtract (5x+16) to put into standard form

Factors of 9·20 = 180 that have a sum of 41 are 5 and 36, so we can rewrite this equation as ...

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  √(5(4)+16) -2 = √36 -2 = 4 . . . . value of the left side for x = 4

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The set of solutions is then ...

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