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3 years ago

Plz help me help me help me

Mathematics

2 answers:

yulyashka [42]3 years ago

8 0

Answer:

Step-by-step explanation: 16 is for the apple juice for when the orange juice is 8 since orange juice is half of the apple juice. For the last one the apple juice is 32 and the orange juice is 16

exis [7]3 years ago

7 0

The answer is this :) hope I helped

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Simplify: <img src="https://tex.z-dn.net/?f=4%5Csqrt%7B320%7D%20-%203%5Csqrt%7B80%7D" id="TexFormula1" title="4\sqrt{320} - 3\sq

aleksandrvk [35]

Answer:

20 √ 5

Step-by-step explanation:

1. You'll need to simplify each term. You'll get 32 √ 5-12 √ 5.

2. After you subtract 12 √ 5 from 32 √ 5, you'll get 20 √ 5.

8 0

3 years ago

The scatter plot shows the number of football and baseball cards collected by a sample of third grade children. A coordinate pla

larisa [96]

If your question looks like mine (shown in picture).Your answer would be number 4.
Hope this helps!
CTPehrson

6 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST! PLEASE HELP! Write 206 in base 7

Anna71 [15]

Answer:

413_7

Step-by-step explanation:

Convert the following to base 7:

206_10

Hint: | Starting with zero, raise 7 to increasingly larger integer powers until the result exceeds 206.

Determine the powers of 7 that will be used as the places of the digits in the base-7 representation of 206:

Power | \!$\*SuperscriptBox[\(Base$, $Power$]\) | Place value

3 | 7^3 | 343

2 | 7^2 | 49

1 | 7^1 | 7

0 | 7^0 | 1

Hint: | The powers of 7 (in ascending order) are associated with the places from right to left.

Label each place of the base-7 representation of 206 with the appropriate power of 7:

Place | | | 7^2 | 7^1 | 7^0 |

| | | ↓ | ↓ | ↓ |

206_10 | = | ( | __ | __ | __ | )_(_7)

Hint: | Divide 206 by 7 and find the remainder. The remainder is the first digit from the right.

Determine the value of the first digit from the right of 206 in base 7:

206/7=29 with remainder 3

Place | | | 7^2 | 7^1 | 7^0 |

| | | ↓ | ↓ | ↓ |

206_10 | = | ( | __ | __ | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 29, by 7 and find the remainder. The remainder is the next digit.

Determine the value of the next digit from the right of 206 in base 7:

29/7=4 with remainder 1

Place | | | 7^2 | 7^1 | 7^0 |

| | | ↓ | ↓ | ↓ |

206_10 | = | ( | __ | 1 | 3 | )_(_7)

Hint: | Divide the whole number part of the previous quotient, 4, by 7 and find the remainder. The remainder is the last digit.

Determine the value of the last remaining digit of 206 in base 7:

4/7=0 with remainder 4

Place | | | 7^2 | 7^1 | 7^0 |

| | | ↓ | ↓ | ↓ |

206_10 | = | ( | 4 | 1 | 3 | )_(_7)

Hint: | Express 206_10 in base 7.

The number 206_10 is equivalent to 413_7 in base 7.

Answer: 206_10 =413_7

5 0

2 years ago

4. Exchanging one good for another is called

Sonbull [250]

Answer: Barter

Step-by-step explanation: hope this helps

4 0

3 years ago

Read 2 more answers

Will get branliest!!!!!!!

lawyer [7]

Answer:

It has the same domain as the function $f(x)=-\sqrt{-x}$

Step-by-step explanation:

we have

$f(x)=\sqrt{-x}$

we know that

The radicand cannot be a negative number

$-x\geq 0$

Solve for x

Multiply by -1 both sides

$x\leq 0$

The domain of the given function is the interval ----> (-∞,0]

All real numbers less than or equal to 0

The range of the given function is the interval ----> [0,∞)

All real numbers greater than or equal to zero

Verify each statement

Part 1) It has the same domain as the function $f(x)=-\sqrt{-x}$

The statement is true

The domain of the function $f(x)=-\sqrt{-x}$ is

the interval ---> (-∞,0]

Part 2) It has the same range as the function $f(x)=-\sqrt{-x}$

The statement is false

The range of the function $f(x)=-\sqrt{-x}$ is

the interval ---> (-∞,0]

Part 3) It has the same domain as the function $f(x)=-\sqrt{x}$

The statement is false

The domain of the function $f(x)=-\sqrt{x}$ is

the interval ---> [0,∞)

Part 4) It has the same range as the function $f(x)=-\sqrt{x}$

The statement is false

The range of the function $f(x)=-\sqrt{x}$ is

the interval ---> (-∞,0]

4 0

3 years ago

Read 2 more answers