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Ierofanga [76]
3 years ago
11

3x-4y=16 and 5x+2y=44 using elimination strategy and comparing strategy

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
5 0

3x-4y=16 \\5x+2y=44 \\ \\3x-4y=16 \\10x+4y=88 \\ \\13x=104 \\x=\boxed{104\div13=8}\\ \\3\times8-4y=16 \\24-4y=16 \\-4y=-8 \\y=\boxed{2}

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mario62 [17]

Answer:

The answer is B.

Step-by-step explanation:

Diameter x Pi = Circumference

8 x 3.14 = 25.12

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3 years ago
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Someone please help...i’m trying to get my grade up.
WARRIOR [948]

Answer:

y=2

Step-by-step explanation:

4 0
2 years ago
This math my graduation depends on it
In-s [12.5K]

In an arithmetic sequence, consecutive terms have a fixed distance d between them. If a₁ is the first term, then

2nd term = a₂ = a₁ + d

3rd term = a₃ = a₂ + d = a₁ + 2d

4th term = a₄ = a₃ + d = a₁ + 3d

and so on, up to

nth term = a_n = a_{n-1} + d = a_{n-2} + 2d = a_{n-3} + 3d = \cdots = a_1 + (n-1)d

so that every term in the sequence can be expressed in terms of a₁ and d.

6. It's kind of hard to tell, but it looks like you're given a₁₃ = -53 and a₃₅ = -163.

We have

a₁₃ = a₁ + 12d = -53

a₃₅ = a₁ + 34d = -163

Solve for a₁ and d. Eliminating a₁ and solving for d gives

(a₁ + 12d) - (a₁ + 34d) = -53 - (-163)

-22d = 110

d = -5

and solving for a₁, we get

a₁ + 12•(-5) = -53

a₁ - 60 = -53

a₁ = 7

Then the nth term is recursively given by

a_n = a_{n-1}-5

and explicitly by

a_n = 7 + (n-1)(-5) = 12 - 5n

7. We do the same thing here. Use the known terms to find a₁ and d :

a₁₉ = a₁ + 18d = 15

a₃₈ = a₁ + 37d = 72

⇒   (a₁ + 18d) - (a₁ + 37d) = 15 - 72

⇒   -19d = -57

⇒   d = 3

⇒   a₁ + 18•3 = 15

⇒   a₁ = -39

Then the nth term is recursively obtained by

a_n = a_{n-1}+3

and explicitly by

a_n = -39 + (n-1)\cdot3 = 3n-42

8. I won't both reproducing the info I included in my answer to your other question about geometric sequences.

We're given that the 1st term is 3 and the 2nd term is 12, so the ratio is r = 12/3 = 4.

Then the next three terms in the sequence are

192 • 4 = 768

768 • 4 = 3072

3072 • 4 = 12,288

The recursive rule with a₁ = 3 and r = 4 is

a_n = 4a_{n-1}

and the explicit rule would be

a_n = 3\cdot4^{n-1}

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2 years ago
What is the y-intercept of a line thay has a slope of 3 and passes through point (-1,-7)
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The answer is y= 3x -4
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3 years ago
|x-3|= - 2 1/4 Math question
AlladinOne [14]

Answer:

No solution

Step-by-step explanation:

Absolute value can not output a negative result

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