Subtract 33 from both sides
6x>3x+30-36x>3x+30−3
Simplify 3x+30-33x+30−3 to 3x+273x+27
6x>3x+276x>3x+27
Subtract 3x3x from both sides
6x-3x>276x−3x>27
Simplify 6x-3x6x−3x to 3x3x
3x>273x>27
Divide both sides by 3
3x>\frac{27}{3}x>
3x> 27
Simplify \frac{27}{3}
3
ANSWER: x>9
Answer:
y= 3x+16
Step-by-step explanation:
y = 3x + 8 ║ y= mx +b
Since lines are parallel, m=3
y= 3x+b
(-3, 7) intersect
y= 3x+16
Answer:
Given, two numbers 56 and 57 we need to find out the numbers lie between the squares of the given numbers.
Now, we have numbers lying between the square of n and (n + 1) is 2n
⇒ Numbers between squares of 56 and (56 + 1) = 2 × 56 = 112
Hence, 112 numbers lies between the square of the given numbers.
Using BEDMAS, it would be brackets first, so anything Inside a set of brackets would be solved first, and would follow the same rule. Once the brackets have been solved, next would be the exponents. Since your brackets have been solved you can expand with the exponents. After exponents, would be anything that has to be divided or multiplied. These two operations are interchangeable based on what is more convenient or beneficial to do first. And lastly, addition and subtraction, which once again are interchangeable operations
The answer for the following is B
