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4 years ago

13

Evaluate 2(4-1) exponent 2.

1 answer:

adelina 88 [10]4 years ago

3 0

(2 * (4-1) )^2

I'm assuming that's what the problem is.

(2 * 3) ^2

6^2

36

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Need help on this question please

aleksley [76]

Answer:

The answer to your question is: neither parallel nor perpendicular.

Step-by-step explanation:

Data

x - 7y = 10 ---(1) and 2x + 14y = 21 ---- (2)

First we need to clear y from two equations

7y = x -10 14y = -2x +21

y = x/7 - 10/7 y = -2/14 x + 21/14

y = -1/7 x + 3/2

slope = 1/7 slope = -1/7

They are neither parallel nor perpendicular, if they were parallel the slopes will be the same, if they were perpendicular they would have inverse values.

7 0

3 years ago

A movie ticket costs $12 with a discount of 5%. What is the amount of discount and the sale price?

Alexeev081 [22]

Answer:

0.6

Step-by-step explanation:

5 0

3 years ago

You estimate that a baby pig weighs 20 pounds. The actual weight of the baby pig is 16 pounds. Find the percent error.

vagabundo [1.1K]

Answer:

25%

Step-by-step explanation:

percent error is found by the equation(measured-real)/real x 100

20 is the measured value and 16 is the real value

(20-16)/16 x 100

4/16 x 100

0.25 x 100

25

hope this helps!

8 0

2 years ago

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

strojnjashka [21]

Answer:

The missing side is $B = 6.0\ cm$

The missing angles are $\alpha = 56.2$ and $\theta = 93.8$

Step-by-step explanation:

Given

$A = 10\ cm$

$C = 12\ cm$

$\beta = 30$

The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with $\alpha$

Angle B with $\beta$

Angle C with $\theta$

Calculating B

This will be calculated using cosine formula as thus;

$B^2 = A^2 + C^2 - 2ACCos\beta$

Substitute values for A, C and $\beta$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30$

$B^2 = 100 + 144 - 240 * 0.8660$

$B^2 = 100 + 144 - 207.8$

$B^2 = 36.2$

Take Square root of both sides

$B = \sqrt{36.2}$

$B = 6.0$ <em>(Approximated)</em>

Calculating $\alpha$

This will be calculated using cosine formula as thus;

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute values for A, B and C

$A^2 = B^2 + C^2 - 2BCCos\alpha$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha$

$100 = 36 + 144 - 144Cos\alpha$

Collect Like Terms

$100 - 36 - 144 = -144Cos\alpha$

$-80 = -144Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = Cos\alpha$

$0.5556 = Cos\alpha$

$\alpha = cos^{-1}(0.5556)$

$\alpha = 56.2$ <em>(Approximated)</em>

Calculating $\theta$

This will be calculated using cosine formula as thus;

$C^2 = B^2 + A^2 - 2BACos\theta$

Substitute values for A, B and C

$12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta$

$144 = 36 + 100 - 120Cos\theta$

Collect Like Terms

$144 - 36 - 100 = -120Cos\theta$

$8 = -120Cos\theta$

Divide both sides by -120

$\frac{8}{-120} = Cos\theta$

$-0.0667= Cos\theta$

$\theta = cos^{-1}(-0.0667)$

$\theta = 93.8$ <em>(Approximated)</em>

4 0

4 years ago

Pls help me i need to write this for an exam

Marrrta [24]

13 nehrdjyyk ivihudkihpyvkjj ty

7 0

3 years ago

Read 2 more answers