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MakcuM [25]
3 years ago
10

Find the vertex. 4) y=-2x^2-8x-6

Mathematics
1 answer:
Alexxx [7]3 years ago
3 0

Answer:

Vertex: (-2, 2)

Step-by-step explanation:

The x-coordinate of the vertex would be as follows;

x = -b/2a = 8/2(-2) = -8/4 = -2

respectively the y-coordinate of the vertex would be y(-2) = -2(-2)^2 - 8(-2) - 6 = -2(4) + 16 - 6 = - 8 + 10 = 2

Your vertex would be a maximum of (-2, 2)

* I say maximum as the coefficient of x^2 is -2, and it is less than zero so the parabola opens downward

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Mandarinka [93]

Answer:

Alright so i simplified the expression Which gives me the Answer

- 3m/2 + 2p - 1/8 Hope this helps :)

Step-by-step explanation:


8 0
4 years ago
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CL 2-107. Solve for w(show work): 6w - 5 + 8w - 2w - 3 = 9w - 24​
jekas [21]

Answer:

w = -16/3

Step-by-step explanation:

6w - 5 + 8w - 2w - 3 = 9w - 24​

Combine like terms

12w -8 = 9w -24

Subtract 9w from each side

12w -9w -8 = 9w -9w -24

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Add 8 to each side

3w-8+8 = -24+8

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7 0
3 years ago
Can I get some help on this one and if you could show its done I would appreciate it. Thank you.
Andreyy89
<h3>Answer: 5.5 which is choice B</h3>

Have a look at the diagram I posted below. I marked on your image to add in another angle. This angle is also 20 degrees because of congruent alternate interior angles (horizontal lines are parallel). This angle I add in is the reference angle of the triangle

opposite the reference angle is the vertical side x

adjacent to the reference angle is the horizontal side 15

We'll use the tangent rule. Make sure your calculator is in degree mode.

tan(angle) = opposite/adjacent

tan(20) = x/15

15*tan(20) = x <<-- multiply both sides by 15

x = 15*tan(20)

x = 5.45955 <<--- use calculator; this is approximate

x = 5.5 <<--- round to one decimal place

5 0
4 years ago
Find slope of line with the points (-5,-4) and has a slope of -3/5
marishachu [46]

Answer:

-3/5

Step-by-step explanation:

The answer is already in your question. You're asking for the slope of a line with an already stated slope

6 0
3 years ago
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Please help me ! Thank you so much if you do .
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What is the opinions? For the drop down menu. :)
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