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blondinia [14]
3 years ago
12

Please help me solve #6 and #8 Also explain

Mathematics
1 answer:
Vesna [10]3 years ago
4 0
Transitive property
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Solve each quadratic equation by factoring <br> X+3=24x
melomori [17]
X+3=24x :)))))))))))))))))))))
4 0
3 years ago
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Which sequence could be partially defined by the recursive formula f (n + 1) = f(n) + 2.5 for n ≥ 1?
Stells [14]
<span>–10, –7.5, –5, –2.5, …

Is defined by the formula because the next term can be obtained by adding 2.5 to the current one.</span>
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3 years ago
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Can x3 – 3x + 1 be the quotient on division of x5+ 2x3 + x – 1 by a polynomial in x of degree 3? Justify​
mestny [16]

Answer:

No

Step-by-step explanation:

x⁵ + 2x³ + x - 1  -> degree of  the polynomial is 5

So, when x⁵ is divided by x³, the quotient should be x⁵⁻³ = x².

So, x³ - 3x + 1 cannot be a quotient

8 0
3 years ago
How many months old is Paula?
oksano4ka [1.4K]

Answer:

we cant just tell that. we need numbers. and problems.

Step-by-step explanation:

8 1
3 years ago
Consider the following points on cartesian plane. A (1;2) BC3; 1) and CG-3; 4) prove that Points A, B and C are collinear. ​
Arlecino [84]

Step-by-step explanation:

Collinear points have the same gradient

find the gradient(slope) between AB first

= \frac{1 - 2}{3 - 1}  \\  =  \frac{ - 1}{2}

Find the one for BC

= \frac{4 - 1}{ - 3 - 3}  \\  =  \frac{3}{ - 6}  \\  =  \frac{ - 1}{2}

Find the gradient between AC now

=  \frac{4 - 2}{ - 3 - 1}  \\  =  \frac{2}{ - 4}  \\  =  \frac{ - 1}{2}

YOUR LAST STATEMENT NOW WILL BE

POINTS A,B AND C ARE COLLINEAR SINCE THE GRADIENTS BETWEEN THEM IS THE SAME!!!

5 0
2 years ago
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