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tankabanditka [31]
3 years ago
10

What is the measure, in degrees, of ZA?

Mathematics
2 answers:
Elza [17]3 years ago
8 0

Answer:

Step-by-step explanation:

We know that the sum of interior angles of a triangle is 180° so we can say:

40 + 2x + 3x = 180°

40 + 5x = 180°

5x = 140°

x = 28°

Now substitute in 28 for the value of x in Angle A:

=> 2x would become 2(28)

=> 56° = ∠A

Hope this helps!

vesna_86 [32]3 years ago
6 0

Answer:

28

Step-by-step explanation:

2x + 3x + 40 =180

5x= 180 - 140

5x=140

x= 28

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Zinaida [17]

Answer:

Step-by-step explanation:

Remark

Read the following carefully.

There is a beautiful theorem that has to do with the endpoints of two angles sharing the same endpoints.  

To be a little clearer, I hope, that makes < BAC = <BDC because both angles have B and C as their endpoints inside the circle. Make sure you understand that statement before moving on.

For this problem <BDC = <CAB = 33 degrees.

That means that ADC = 37 + 33 = 70

Solution

<ADC and CBA are opposite angles.

That means that they add to 180

From the above statement in the Remark section <ADC = 37 + 33 = 70 degrees <ABD + <DBC = <ABC = m + 71

<ABC + ADC = 180

m + 71 + 70 = 180        Combine

m + 141 = 180               Subtract 141 from both sides.

m+141-141= 180 - 141    Combine

m = 39

Answer: m = 39

3 0
2 years ago
Find equations for those tangent lines to<br> the graph of<br> y = x − 3/x
pychu [463]

Step-by-step explanation:

y=X -3/X

y=X/1 -3/x

y= 2x -3/x

y*X= 2x-3

y*X/2 = x-3

7 0
3 years ago
PLEASE I REALLY NEED HELP&gt; DONT SKIP. NO LINKS PLEASE. BRANLIEST WILL BE GIVEN
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Answer:

A. 165 ft²

Step-by-step explanation:

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8 0
3 years ago
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Find the minimum and maximum values of the function subject to the given constraint. (if an answer does not exist, enter dne.) f
nata0808 [166]
Via Lagrange multipliers:

L(x,y,\lambd)=x^2y+x+y+\lambda(xy-5)
L_x=2xy+1+\lambda y=0
L_y=x^2+1+\lambda x=0
L_\lambda=xy-5=0

\underbrace{10}_{2xy}+1+\lambda y=0\implies \lambda=-\dfrac{11}y
xy=5\implies y=\dfrac5x\implies\lambda=-\dfrac{11}5x

\impliesx^2+1+\left(-\dfrac{11}5x\right)x=0\implies x^2=\dfrac56\implies x=\pm\sqrt{\dfrac56}
xy=5\implies y=\pm\sqrt{30}

At these points, we get local minima of f\left(\pm\sqrt{\dfrac56},\pm\sqrt{30}\right)=\pm2\sqrt{30}.

- - -

Another way to do this is to make f(x,y) a function independent of y, which is made possible by the constraint.

xy=5\implies y=\dfrac5x
\implies f(x,y)=f\left(x,\dfrac5x\right)=F(x)=6x+\dfrac5x
\implies F'(x)=6-\dfrac5{x^2}=0\implies x=\pm\sqrt{\dfrac56}

and so on.
8 0
3 years ago
Find in cm the diameter of a circle whose radius is 85 mm.
vazorg [7]
Well, you first have to convert the 85 mm to cm, which you divide it by 100, and you get 8.5 cm, then add that with itself and you get 17 cm.
6 0
3 years ago
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