Answer: negative 9 square root of 11
explanation:
5√11 - 12√11 - 2√11
collect like terms by calculating the sum or difference of their coefficients:
(5-12-2) √11
(5-12-2) = (5-14) = -9
so, -9√11
Given that the diameter: d= 0.0625 inch.
So, radius of the wire : r =
= 0.03125 inch
Now the formula to find the cross-sectional area of wire ( circle) is:
A = πr²
= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125
=3.14 * 0.000976563
= 0.003066406
= 0.00307 (Rounded to 5 decimal places).
Hence, cross-sectional area of a wire is 0.00307 square inches.
Hope this helps you!
Answer:
C
Step-by-step explanation:
Since "P" is -4, add POSITIVE 6.5 to it. It makes 2.5
hope it helps :D
Looking at the problem statement, this question states for us to determine the range of the function that is provided in a graph is. Let us first determine what range is.
- Range ⇒ Range is what y-values can be used in the function that is graphed. For example, if a line just goes up and down all the way to negative and positive infinity, then the range would be negative infinity to positive infinity as it includes all of the y-values in it's solutions.
Now moving back to our problem, we can see that we have a vertex at (2, -5) and that the lowest y-values is at y = -5. Therefore the y-values would be anything greater than or equal to -5 and less than infinity because the lines go forever up in the positive-y-direction.
Therefore, the option that would best match the description that we provided would be option B, -5 ≤ y < ∞.