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Ivan
3 years ago
11

Choose the function whose graph is given by:

Mathematics
2 answers:
xeze [42]3 years ago
6 0

Answer:

Option B. y = cosx + 1

Step-by-step explanation:

To understand the given graph we will note down it's features as below.

1). Since it's a periodic function and y value of graph is maximum at x=0 so its a cosine function.

2). Vertical shift of the graph is 1 means y=0 is the mid line of the graph.

3). Amplitude of the graph is = (2-0)/2 = 1

4). Phase shift of the given graph = 0

The graph satisfying all properties is option B. y = cosx + 1

Daniel [21]3 years ago
4 0

Answer:

The correct option is B.

Step-by-step explanation:

From the given graph it is clear that the maximum value of the function is 2 at x=0, so it a cosine function.

The general form of a cosine function is

y=a\cos(bx+c)+d       .... (1)

Where, a is amplitude, 2π/b is period, c is phase shift and d is midline.

Since maximum value is 2 and minimum value is 0, so

Amplitude=a=\frac{2-0}{2}=1

Midline=b=\frac{2+0}{2}=1

Period=2\pi\Rightarrow b=1

Since maximum value is at x=0, therefore the phase shift is c=0.

Put these values in equation 1.

y=1\cos(1x+0)+1

y=\cos(x)+1

Therefore the correct option is B.

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Simplify 5 square root of 11 end root minus 12 square root of 11 end root minus 2 square root of 11 . (1 point)
Luden [163]
Answer: negative 9 square root of 11
explanation:
5√11 - 12√11 - 2√11
collect like terms by calculating the sum or difference of their coefficients:
(5-12-2) √11
(5-12-2) = (5-14) = -9
so, -9√11
5 0
4 years ago
A function f has the property that f(x-y)=f(x)/(y) f(y) does not equal zero if f (8)=256and f(5)=32 what is the value of f(3)
Dvinal [7]

Answer:

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3 0
3 years ago
What is the cross-sectional area of a wire if its outside diameter is 0.0625 inch?
Leno4ka [110]

Given that the diameter: d= 0.0625 inch.

So, radius of the wire : r = \frac{0.0625}{2} = 0.03125 inch

Now the formula to find the cross-sectional area of wire ( circle) is:

A = πr²

= 3.14 * (0.03125)² Since, π = 3.14 and r = 0.03125

=3.14 * 0.000976563

= 0.003066406

= 0.00307 (Rounded to 5 decimal places).

Hence, cross-sectional area of a wire is 0.00307 square inches.

Hope this helps you!

5 0
3 years ago
Read 2 more answers
Can u pls help me with this question asap ​
Annette [7]

Answer:

C

Step-by-step explanation:

Since "P" is -4, add POSITIVE 6.5 to it. It makes 2.5

hope it helps :D

7 0
3 years ago
Hey guys my last question please answer :) peace and love guys
Vadim26 [7]

Looking at the problem statement, this question states for us to determine the range of the function that is provided in a graph is.  Let us first determine what range is.

  • Range ⇒ Range is what y-values can be used in the function that is graphed.  For example, if a line just goes up and down all the way to negative and positive infinity, then the range would be negative infinity to positive infinity as it includes all of the y-values in it's solutions.

Now moving back to our problem, we can see that we have a vertex at (2, -5) and that the lowest y-values is at y = -5.  Therefore the y-values would be anything greater than or equal to -5 and less than infinity because the lines go forever up in the positive-y-direction.

Therefore, the option that would best match the description that we provided would be option B, -5 ≤ y < ∞.

5 0
2 years ago
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