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3 years ago

64 movie tickets are sold. 5/8 of the tickets were for adult admission. How many adult admission tickets were sold?

Mathematics

2 answers:

charle [14.2K]3 years ago

7 0

First take note 64 tickets were sold in total and 5/8 of those tickets were for adults.

To solve this you must first make 5/8 a decimal and to do so you will divide 5 by 8.

which is equal to .625

Now multiply 65 by .625

Which will equal 40.42500

So the answer is 40

Neko [114]3 years ago

5 0

40 adult admission tickets were sold

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ELEN [110]

Answer:

d = 233.23 feet

Step-by-step explanation:

Given that,

Justin walks 200 feet to the east, then turns and walks 120 feet due south.

We need to find the total distance walked by Justin. Let the distance be d.

We can use the Pythagoras theorem to find it such that,

$d=\sqrt{d_1^2+d_2^2} \\\\d=\sqrt{200^2+120^2} \\\\d=233.24\ feet$

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Blababa [14]

Answer:

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = 0.0228

Step-by-step explanation:

Step(i):-

Given mean of the Population = 500

Given standard deviation of the Population = 50

Let 'X' be the random variable in normal distribution

Given X = 600

$Z = \frac{x-mean}{S.D} = \frac{600-500}{50} = \frac{100}{50} =2$

Step(ii):-

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = P(z≥2)

= 0.5 - A(2)

= 0.5 -0.4772

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Final answer:-

The probability that the candidate score is 600 or greater

P(X≥ 600 ) = 0.0228

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Lyrx [107]

For this case, the first thing we should do is use the following equation:
x ^ 2 + x-30
Here, we substitute the value of x = 20
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the area of the land when the length of the dentist's office is 20 meters is:
390 m ^ 2

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3 years ago

HELP ASAP FOR BRAINLIEST: The time required to finish a test in normally distributed with a mean of 60 minutes and a standard de

liubo4ka [24]

Answer:

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Step-by-step explanation:

1. Let's review the information given to us to answer the question correctly:

Mean of time to finish a test = 60 minutes

Standard deviation of time to finish a test = 10 minutes

Time that a student finishes the test = 23 minutes

2. What is the z-score for the student?

z-score = (Time that a student finishes the test - Mean of time to finish a test)/Standard deviation of time to finish a test

Replacing with the real values:

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3 years ago