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djyliett [7]
4 years ago
10

6. 7 ≥ - 0. 2 x + 4. 5 solve the inequality

Mathematics
2 answers:
labwork [276]4 years ago
7 0

Answer:

-11≤x

Step-by-step explanation:

Given

6.7 ≥ -0.2x +4.5----------------collect like terms

6.7-4.5 ≥ -0.2x--------------divide by -0.2 both sides

2.2/-0.2 ≥ -0.2/-0.2x-------------------reverse the sign

-11 ≤ x

Alekssandra [29.7K]4 years ago
5 0

For this case we have the following inequality:

6.7\geq 0.2x + 4.5

Subtracting 4.5 from both sides of the inequality:

6.7-4.5\geq -0.2x\\2.2\geq -0.2x

Dividing between 0.2 on both sides:

\frac {2.2} {0.2} \geq-x\\11 \geq-x

We multiply by -1 on both sides, taking into account that the sense of inequality changes:

-11 \leq x

ANswer:

x \geq-11

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Race times at the local monthly 5k run are normally distributed, with a mean time of 32 minutes and a standard deviation of 4 mi
galina1969 [7]

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68%

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So the answer is 68%.

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4 years ago
Let f(x,y,z) = ztan-1(y2) i + z3ln(x2 + 1) j + z k. find the flux of f across the part of the paraboloid x2 + y2 + z = 3 that li
Sophie [7]
Consider the closed region V bounded simultaneously by the paraboloid and plane, jointly denoted S. By the divergence theorem,

\displaystyle\iint_S\mathbf f(x,y,z)\cdot\mathrm dS=\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV

And since we have

\nabla\cdot\mathbf f(x,y,z)=1

the volume integral will be much easier to compute. Converting to cylindrical coordinates, we have

\displaystyle\iiint_V\nabla\cdot\mathbf f(x,y,z)\,\mathrm dV=\iiint_V\mathrm dV
=\displaystyle\int_{\theta=0}^{\theta=2\pi}\int_{r=0}^{r=1}\int_{z=2}^{z=3-r^2}r\,\mathrm dz\,\mathrm dr\,\mathrm d\theta
=\displaystyle2\pi\int_{r=0}^{r=1}r(3-r^2-2)\,\mathrm dr
=\dfrac\pi2

Then the integral over the paraboloid would be the difference of the integral over the total surface and the integral over the disk. Denoting the disk by D, we have

\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-\iint_D\mathbf f\cdot\mathrm dS

Parameterize D by

\mathbf s(u,v)=u\cos v\,\mathbf i+u\sin v\,\mathbf j+2\,\mathbf k
\implies\mathbf s_u\times\mathbf s_v=u\,\mathbf k

which would give a unit normal vector of \mathbf k. However, the divergence theorem requires that the closed surface S be oriented with outward-pointing normal vectors, which means we should instead use \mathbf s_v\times\mathbf s_u=-u\,\mathbf k.

Now,

\displaystyle\iint_D\mathbf f\cdot\mathrm dS=\int_{u=0}^{u=1}\int_{v=0}^{v=2\pi}\mathbf f(x(u,v),y(u,v),z(u,v))\cdot(-u\,\mathbf k)\,\mathrm dv\,\mathrm du
=\displaystyle-4\pi\int_{u=0}^{u=1}u\,\mathrm du
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\displaystyle\iint_{S-D}\mathbf f\cdot\mathrm dS=\frac\pi2-(-2\pi)=\dfrac{5\pi}2
6 0
4 years ago
Mr. James has cylindrical beakers that measure 4 inches in diameter and 9 inches high. What is the volume contained within the b
goblinko [34]
So 4 inches diameter result the radius is 4/2 = 2 inches 

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volume = area of base *height 

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hope this will help you 
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3 years ago
Can a -150/10 be classified as both a rational number and a integer
irakobra [83]
Yes! This is because -150/10 can be simplified to be -15, which is a rational number.

The word “rational” sounds like another math word you’ve heard of before. Do you know what it is?

Well, it’s “ratio”!! Ratios can be seen in the forms x:y and x/y.


ANY RATIONAL NUMBER HAS THE ABILITY TO BE WRITTEN AS A RATIO!! This will completely exclude numbers with super long decimal points (ex: 1.2345678809928374737272828...)

This number also meets the requirements of being an integer. An integer is any whole number (this excludes decimals and fractions)

I know it’s written as a fraction. However, the fraction could be simplified, making it -15, which means this is both a rational number and an integer!!
6 0
3 years ago
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