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docker41 [41]
3 years ago
10

Solve 4_3=3x+y=2y+5x_12​

Mathematics
1 answer:
serious [3.7K]3 years ago
4 0

Answer:

It's not possible.

Step-by-step explanation:

It has two equals sign and an underscore. make sure yu have the right equation.

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What is the formula of circle​
gogolik [260]

Answer:

Area = pi r squared

Step-by-step explanation:

If you need to, sometimes your teacher will ask you to leave you answers in terms of pi, or keep pi as 3.

3 0
2 years ago
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Convert 3/11 to a decimal using long division
stepladder [879]
3/11 as a decimal is .27 repeating that means it has a line over the two and the seven but if you want to round it would be .3
5 0
3 years ago
Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10
zvonat [6]

The approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

<h3>What is depreciation?</h3>

Depreciation is to decrease in the value of a product in a period of time. This can be given as,

FV=P\left(1-\dfrac{r}{100}\right)^n

Here, (<em>P</em>) is the price of the product, (<em>r</em>) is the rate of annual depreciation and (<em>n</em>) is the number of years.

Two different cars each depreciate to 60% of their respective original values. The first car depreciates at an annual rate of 10%.

Suppose the original price of the first car is x dollars. Thus, the depreciation price of the car is 0.6x. Let the number of year is n_1. Thus, by the above formula for the first car,

0.6x=x\left(1-\dfrac{10}{100}\right)^{n_1}\\0.6=(1-0.1)^{n_1}\\0.6=(0.9)^{n_1}

Take log both the sides as,

\log 0.6=\log (0.9)^{n_1}\\\log 0.6={n_1}\log (0.9)\\n_1=\dfrac{\log 0.6}{\log 0.9}\\n_1\approx4.85

Now, the second car depreciates at an annual rate of 15%. Suppose the original price of the second car is y dollars.

Thus, the depreciation price of the car is 0.6y. Let the number of year is n_2. Thus, by the above formula for the second car,

0.6y=y\left(1-\dfrac{15}{100}\right)^{n_2}\\0.6=(1-0.15)^{n_2}\\0.6=(0.85)^{n_2}

Take log both the sides as,

\log 0.6=\log (0.85)^{n_2}\\\log 0.6={n_2}\log (0.85)\\n_2=\dfrac{\log 0.6}{\log 0.85}\\n_2\approx3.14

The difference in the ages of the two cars is,

d=4.85-3.14\\d=1.71\rm years

Thus, the approximate difference in the ages of the two cars, which  depreciate to 60% of their respective original values, is 1.7 years.

Learn more about the depreciation here;

brainly.com/question/25297296

4 0
2 years ago
Solve: 6x-9 = 3x<br> A x = 3<br> B x=1<br> C x = -1<br> D X=-3
Bumek [7]

Answer:

Answer is A, A=3

Step-by-step explanation:

3 0
3 years ago
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Please help! Ralph buys a computer for $675. The sales tax rate is 6%. How much did Ralph pay for the computer?
zloy xaker [14]

Answer:

$715.50 my dudeeee

Step-by-step explanation:

..........

4 0
2 years ago
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