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lina2011 [118]
4 years ago
12

What is the value of x in the equation 8x – 2y = 48, when y = 4?

Mathematics
2 answers:
vodka [1.7K]4 years ago
4 0
8x - 2y = 48 ; find x  if y = 4.

x = 7

substitute y with number 4.

8x - 2(4) = 48
8x - 8 = 48

find x. transfer -8 to the other side and change its sign from negative to positive.

8x = 48 + 8
8x = 56

find x. divide both sides by 8.

8x/8 = 56/8
x = 7

to check substitute x with 7 and y with 4.

8x - 2y = 48
8(7) - 2(4) = 48
56 - 8 = 48
48 = 48
vekshin14 years ago
3 0
8x - 2y = 48
If y is given as 4, then "plug it into the equation".
8x - 2(4) = 48 
8x - 8 = 48 --> Add 8 to both sides of the equation to isolate the x variable
8x = 56 --> Divide both sides by 8
x = 7

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3 years ago
Jade and Eliza went shopping at a mall. Jade spent $10 more than 5 times the amount that Eliza spent. Jade spent a total of $150
DaniilM [7]

Answer:

140

Step-by-step explanation:

Let total money spent by Eliza's be represented as x

Five times amount Eliza spent = 5x and total amount spent by Jade is $150

So it will be $10+ 5x =$150

5x= 150- 10

5x= 140

x = 140÷5

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........................

So therefore Eliza's amount spent = $28 and

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8 0
3 years ago
Ill give brainliest please help with this algebra!!
creativ13 [48]

Answer:

Each of these equations solves as 1, because each one of them is an instance of the same expression being divided by itself.

This will <em>always</em> give you a value of 1, as long as the denominator does not end up with a zero value.

Take for instance the third question:

\frac{p^4}{p^4}\\= p^4 \times p^{-4}\\= p^{(4 - 4)}\\= p^0\\= 1

This stands true with all three questions.

HOWEVER

I say this assuming that the 5 following the first brackets in the first question is meant to be an exponent, and not a multiple.  Given that the norm is to make any numeric multiples precede the brackets, I assume it is an exponent. and we're good.

It's not using superscript though, which could mean that they want it multiplied by five instead of raised to the power of.

If that's case, we can solve it the same way we solved question 20.  If the bases are the same, then when multiplying or dividing the terms, you can simply add or subtract the exponents respectively:

\frac{(4x + 2y)\times5}{(4x + 2y)^5}\\= 5(4x + 2y) \times (4x + 2y)^{-5}\\= 5(4x + 2y)^1 \times (4x + 2y)^{-5}\\= 5(4x + 2y)^{1 - 5}\\= 5(4x + 2y)^{-4}\\= \frac{5}{(4x + 2y)^{4}}

Again, this is probably not the correct answer for question 18, as that 5 is almost guaranteed to be meant as an exponent.  If it is instead a coefficient though, then this would be the answer to it.

8 0
3 years ago
Read 2 more answers
What is the slope of a line that is perpendicular to the line shown.
sertanlavr [38]

Answer:

3/4

Step-by-step explanation:

First of all, we need to calculate the slope of the line shown. This can be computed as:

m=\frac{\Delta y}{\Delta x}

where

\Delta y = y_2-y_1 is the increment along the y-direction

\Delta x = x_2 - x_1 is the increment along the x-direction

We can choose the following two points to calculate the slope of the line shown:

(-3,2) and (0,-2)

And so, the slope of the line shown is

m=\frac{-2-(2)}{0-(-3)}=-\frac{4}{3}

Two lines are said to be perpendicular if the slope of the first line is the negative reciprocal of the slope of the second line:

m_2 = -\frac{1}{m_1}

Using m_1 = -\frac{4}{3}, we find that a line perpendicular to the line shown should have a slope of

m_2 = -\frac{1}{-4/3}=3/4

5 0
3 years ago
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