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ziro4ka [17]
3 years ago
10

What is the slope of a line that is perpendicular to the line shown.

Mathematics
1 answer:
sertanlavr [38]3 years ago
5 0

Answer:

3/4

Step-by-step explanation:

First of all, we need to calculate the slope of the line shown. This can be computed as:

m=\frac{\Delta y}{\Delta x}

where

\Delta y = y_2-y_1 is the increment along the y-direction

\Delta x = x_2 - x_1 is the increment along the x-direction

We can choose the following two points to calculate the slope of the line shown:

(-3,2) and (0,-2)

And so, the slope of the line shown is

m=\frac{-2-(2)}{0-(-3)}=-\frac{4}{3}

Two lines are said to be perpendicular if the slope of the first line is the negative reciprocal of the slope of the second line:

m_2 = -\frac{1}{m_1}

Using m_1 = -\frac{4}{3}, we find that a line perpendicular to the line shown should have a slope of

m_2 = -\frac{1}{-4/3}=3/4

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The feet of a commemorative parabolic steel arch 100m high are 200m apart. Determine whether the focus of the arch is above or b
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Engineers want to design passenger seats in commercial aircraft so that they are wide enough to fit 95 percent of adult men. Ass
zimovet [89]

Answer:

z=1.64

And if we solve for a we got

a=14.4 +1.64*1.1=16.204

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Step-by-step explanation:

Let X the random variable that represent the hips breadths of a population, and for this case we know the distribution for X is given by:

X \sim N(14.4,1.1)  

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P(X>a)=0.05   (a)

P(X   (b)

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Using this value we can set up the following equation:

P(X  

P(z

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3 years ago
a used truck for $4,500 he made an agreement with the dealer to put $1,500 and make payments of 350 for the next 10 months that
Aneli [31]
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Total amount paid  = 1500 + 3500 = 5000
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I = PRT
Interest, I = 5000 - 4500 = 500Time, t = 10 months = 10/12 = (5/6) year.Principal P = 4500
R = I /(PT)  R = 500 / (4500*5/6)
R = (500*6) / (4500*5)
R = 0.1333..
R ≈ 13.33 %  per annum.

3 0
3 years ago
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