Answer: question one is d and two is c
Step-by-step explanation: have a great day
Answer:
The equation of the line is y = 4/3x - 8
Step-by-step explanation:
In order to find this, we first have to find the slope of the original line. We do this by solving for y.
3x + 4y = 20
4y = -3x + 20
y = -3/4x + 5
Now that we have the slope of -3/4 we can find the perpendicular slope. The perpendicular slope of any time is the opposite and reciprocal slope. So we flip -3/4 to get -4/3 and then we make it positive (4/3). Now that we have our new slope, we can input it along with the point into point-slope form to find the equation.
y - y1 = m(x - x1)
y - 0 = 4/3(x - 6)
y = 4/3x - 8
Answer:
The value of x = 3.42
Step-by-step explanation:
Formula:
Sin ∅ = Opposite side /Hypotenuse
From the figure we can see a right angled triangle.
One angle is given, hypotenuse = 10 and height = x.
To find the value of x
sin 20 = Opposite side/hypotenuse = x/10
x = 10 * sin 20
= 10 * 0.342 = 3.42
Therefore the value of x = 3.42
Answer:
4
Step-by-step explanation:
Class width is said to be the difference between the upper class limit and the lower class limit consecutive classes of a grouped data. To calculate class width, this formula can be used:
CW = UCL - LCL
Where,
CW= Class width
UCL= Upper class limit
LCL= Lower class limit
From the table above:
For class 1, CW = 64 - 60 = 4
For class 2, CW = 69 - 65 = 4
For class 3, CW = 74 - 70 = 4
For class 4, CW = 79 - 75 = 4
For class 5, CW = 84 - 80 = 4
Therefore, the class width of the grouped data = 4
Answer:
21
Step-by-step explanation:
Add 34 to both sides.
14x = 11x + 63
Subtract 11x from both sides
3x = 63
Divide both sides by 3
21
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