Answer:
1.
= 
2.
= 
3.
= 
4.
= 
Step-by-step explanation:
1. 
Taking LCM of (x+3) and (x+5) which is: (x+3)(x+5)

Prove closure: The value of x≠-3 and x≠-5 because if there values are -3 and -5 then the denominator will be zero.
2. 
Factors of x^2-16 = (x)^2 -(4)^2 = (x-4)(x+4)
Factors of x^2+5x+6 = x^2+3x+2x+6 = x(x+3)+2(x+3) =(x+2)(x+3)
Putting factors

Prove closure: The value of x≠-2 and x≠4 because if there values are -2 and 4 then the denominator will be zero.
3. 
Factors of x^2-9 = (x)^2-(3)^2 = (x-3)(x+3)
Factors of x^2-5x+6 = x^2-2x-3x+6 = x(x-2)+3(x-2) =(x-2)(x+3)
Putting factors

Taking LCM of (x-3)(x+3) and (x-2)(x+3) we get (x-3)(x+3)(x-2)


Prove closure: The value of x≠3 and x≠-3 and x≠2 because if there values are -3,3 and 2 then the denominator will be zero.
4. 
Factors of x^2-5x+6 = x^2-3x-2x+6 = x(x-3)-2(x-3) = (x-2)(x-3)
Factors of x^2-16 = (x)^2 -(4)^2 = (x-4)(x+4)

Converting ÷ sign into multiplication we will take reciprocal of the second term

Prove Closure: The value of x≠2 and x≠4 because if there values are 2 and 4 then the denominator will be zero.
Answer:
subtract 9 from both sides
Step-by-step explanation:
m + 9 = 45 ( subtract 9 from both sides )
m = 36
Answer: 1=x
Step-by-step explanation:
34-7x=15+12x
Add 7x to both sides of equation because the oppisite of -7x is +7x
34-7x+7x=15+12x+7x
34=15+19x
Subtract 15 from both side of equation because the oppisite of 15 is -15
34-15=15-15+19x
19=19x
Divide both sides by 19 to get x alone
19/19=19x/19
1=x
Answer:
-15
Step-by-step explanation:
you substitute.
p = kw
p = 5(-3)
p = -15
Answer:
a is 0,4
Step-by-step explanation: