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3 years ago

Please help me with this question!!

Mathematics

1 answer:

Bess [88]3 years ago

4 0

Answer:

$x=16 * cos(46)$

Step-by-step explanation:

Well, first let's look at our trig identities. We can set up a cosine function using the given angle:

$cos (46^{o} ) = \frac{x}{16}$ (adjacent/hypotenuse)

Then, multiplying both sides by 16 gives us:

$x=16 * cos(46)$

Hope this helps!

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What is the area of 18 1/3 if the height of the window is 3 1/3

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You would find the answer by dividing 3 1/3 from 18 1/3.
55/3 / 10/3
(55/3)(3/10)=55/10=5 1/2
Answer: 5 1/2

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3 years ago

Select all the equations that have the same solution as the equation 3x – 12 = 24

Stolb23 [73]

Your answer will be D and E

7 0

3 years ago

Solve (x to the fourth power - 6) ×7+3=

abruzzese [7]

First multiply everything inside the brackets by seven
7x^4-42+3
Then solve what you can
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You an't solve it further. Is this what you mean? X to the fourth power?

6 0

4 years ago

Find x Thanks for the help in advance!

Marina86 [1]

I'm not sure if this is the easiest way of doing this, but it surely work.

Let the base of the triangle be AB, and let CH be the height. Just for reference, we have

$AH=2,\quad HB=6,\quad AC=x$

Moreover, let CH=y and BC=z

Now, AHC, CHB and ABC are all right triangles. If we write the pythagorean theorem for each of them, we have the following system

$\begin{cases}4+y^2=x^2\\36+y^2=z^2\\x^2+z^2=64\end{cases}$

If we solve the first two equations for y squared, we have

$y^2=x^2-4\\y^2=z^2-36$

And we can deduce

$z^2 = x^2+32$

So that the third equation becomes

$x^2+x^2+32=64 \iff 2x^2 = 32 \iff x^2=16 \iff x=4$

(we can't accept the negative root because negative lengths make no sense)

7 0

3 years ago

What are the x-intercepts of the equation? <img src="https://tex.z-dn.net/?f=r%28x%29%20%3D%20x-1%2Fx%2B4" id="TexFormula1"

cestrela7 [59]

Answer:

The only x-intercept is x = 1

Step-by-step explanation:

The equation is:

$r(x)=\frac{x-1}{x+4}$

We can substitute y for r(x), to write in the notation:

$r(x)=\frac{x-1}{x+4}\\y=\frac{x-1}{x+4}$

To get y-intercept, we put x = 0

and

To get x-intercept, we put y =0

We want to find x-intercepts here, so we substitute 0 into y and solve for x. Shown below:

$y=\frac{x-1}{x+4}\\0=\frac{x-1}{x+4}\\0(x+4)=x-1\\0=x-1\\x=1$

The only x-intercept is x = 1

3 0

3 years ago