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4 years ago

PLEASE HELP!! 9TH K12 GCA LIGHT TEST REVIEW SHEET FOR PHYSICS! 100 POINTS!!

Physics

1 answer:

Svetllana [295]4 years ago

6 0

I got a 100 on this. I took a bunch of snips of it for you. Mine is a little different though. I only have 6 questions and most of yours are the same as mine. And some of yours that I have are in a different order. I hope I helped.

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What information is necessary to describe motion scientifically?

tamaranim1 [39]

Answer is A
to determine an objects true motion, you need velocity, which requires direction, time and distance!

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4 years ago

Read 2 more answers

At a beach the light is generallypartially polarized owing to reflections off sand and water. At a particular beach on a particu

Ne4ueva [31]

Answer:

a) 0.159

b) 0.84

Explanation:

The Horizontal component is 2.3 times the vertical component

Let the horizontal electric field component = $E_{h}$

Let the vertical electric field component = $E_{v}$

The formula for light intensity is given by:

$I = \frac{E_{m} ^{2} }{2c \mu}$ ..............................(1)

$E_{m}$ is the resolution of the vertical and horizontal components, $E_{h} and E_{v}$

$E_{m} ^{2} = E_{h} ^{2} + E_{v} ^{2}$ ..................(2)

Light intensity before the glasses were put on:

$I_{1} = \frac{E_{m} ^{2} }{2c \mu_{1} }$ .............................(3)

Put equation (2) into equation (3)

$I_{1} = \frac{E_{h} ^{2} + E_{v} ^{2}}{2c \mu_{1} }$ .............................(4)

After the glasses were put on the horizontal component vanishes, i.e. $E_{h} = 0$

$I_{2} = \frac{ E_{v} ^{2}}{2c \mu_{2} }$ ...................................(5)

Divide equation (5) by equation (4)

$\frac{I_{2} }{I_{1} } = \frac{E_{v} ^{2} }{E_{h} ^{2} + E_{v} ^{2}}$ ...............................(6)

But $E_{h} = 2.3E_{v}$ ......................(7)

Insert equation (7) into (6)

$\frac{I_{2} }{I_{1} } = \frac{E_{v}^{2} }{(2.3E_{v})^{2} + E_{v} ^{2} } \\\frac{I_{2} }{I_{1} } = \frac{E_{v}^{2} }{5.29E_{v}^{2} + E_{v} ^{2} }\\\frac{I_{2} }{I_{1} } = \frac{E_{v}^{2} }{6.29E_{v}^{2} }\\\frac{I_{2} }{I_{1} } =\frac{1}{6.29} \\$

$\frac{I_{2} }{I_{1} }= 0.159$

b) When the sunbather lies on his side, the vertical component vanishes, i.e $E_{v} = 0$

$\frac{I_{2} }{I_{1} } = \frac{E_{h} ^{2} }{E_{h} ^{2} + E_{v} ^{2}}$

$\frac{I_{2} }{I_{1} } = \frac{(2.3E_{v} )^{2} }{E_{v} ^{2} +(2.3E_{v} )^{2}}$

$\frac{I_{2} }{I_{1} } = \frac{5.29E_{v}^{2} }{E_{v} ^{2} +5.29E_{v}^{2} }$

$\frac{I_{2} }{I_{1} } = \frac{5.29E_{v}^{2} }{6.29E_{v}^{2} }\\\frac{I_{2} }{I_{1} } = \frac{5.29}{6.29} \\\frac{I_{2} }{I_{1} } = 0.84$

8 0

3 years ago

An orienteer runs 400m directly east and then 500m to the northeast (at a 45 degree andle from due east and from due north). Pro

Aleks04 [339]

Answer:

Final displacement with respect to the starting position is 832.37 meter

Explanation:

Lets consider that the orienteer start to run on the point of (0,0) point of a coordinate system. When he runs towards to east side about 400m, he will be at the point A(400,0). After he runs to the northeast (at a 45 degree angle from due east and from due north), approximately he will make 353.55 meter to east and 353.55 meter to the north side and he will be at the point of B(753.55, 353.55)

From the starting point total displacement will be 832.37 meter. Please check the attached graphical solution.

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3 years ago

Ice freezes at 32 degrees, but can it get colder then tgat

strojnjashka [21]

No ice is either 32 degrees Fahrenheit or 0 degrees Celsius but that's only normal ice, dry ice is a different story but I'm assuming you're talking about normal ice

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4 years ago

The scalar product of two vectors 2N,4N is 4 angle between them

Angelina_Jolie [31]

Answer:

60°

Explanation:

The scalar product of two vectors with an angle ∅ between them is defined as:

$\overrightarrow{a}\cdot \overrightarrow{b}=|a||b|cos\phi$