1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ann [662]
4 years ago
10

PLEASE HELP!! 9TH K12 GCA LIGHT TEST REVIEW SHEET FOR PHYSICS! 100 POINTS!!

Physics
1 answer:
Svetllana [295]4 years ago
6 0

I got a 100 on this. I took a bunch of snips of it for you. Mine is a little different though. I only have 6 questions and most of yours are the same as mine. And some of yours that I have are in a different order. I hope I helped.

You might be interested in
5. George walks to a friend's house. He walks 750 meters North, then realizes he walked too far.
dedylja [7]

Answer:

Average speed: approximately 76.9\; {\rm m\cdot s^{-1}}.

Average velocity: approximately 38.5\; {\rm m \cdot s^{-1}} (to the north.)

Explanation:

Consider an object that travelled along a certain path. Distance travelled would be equal to the length of the entire path.

In contrast, the magnitude of displacement is equal to distance between where the object started and where it stopped.

In this question, the path George took required him to travel 750\; {\rm m} + 250\; {\rm m} = 1000\; {\rm m} in total. Hence, the distance George travelled would be 1000\; {\rm m}. However, since George stopped at a point (750\; {\rm m} - 250\; {\rm m}) = 500\; {\rm m} to the north of where he started, his displacement would be only 500\; {\rm m} to the north.

Divide total distance by total time to find the average speed.

Divide total displacement by total time to find average velocity.

The total time of travel in this question is 13\; {\rm s}.. Therefore:

\begin{aligned}\text{average speed} &= \frac{\text{total distance}}{\text{total time}} \\ &= \frac{1000\; {\rm m}}{13\; {\rm s}} \\ &\approx 76.9\; {\rm m\cdot s^{-1}}\end{aligned}.

\begin{aligned}\text{average velocity} &= \frac{\text{total displacement}}{\text{total time}} \\ &= \frac{500\; {\rm m}}{13\; {\rm s}} && \genfrac{}{}{0px}{}{(\text{to the north})}{}\\ &\approx 38.5\; {\rm m\cdot s^{-1}} && (\text{to the north})\end{aligned}.

3 0
2 years ago
You have been feeling stressed lately, and you know that you tend to overeat when you are stressed. What can you do to combat th
just olya [345]
Exercise to reduce stress
7 0
4 years ago
Read 2 more answers
What unit do we use for pressure
-Dominant- [34]

Answer:

Pascal

Explanation:

5 0
3 years ago
Read 2 more answers
Water flows over a section of Niagara Falls at a rate of 2.2 × 106 kg/s and falls 65 m. What is the power wasted by the waterfal
Irina-Kira [14]

Answer:

P = 1401.4 x 10⁶ W

Explanation:

Given that

Water flow rate m = 2.2 x 10⁶ kg/s

Height ,h= 65 m

Acceleration due to gravity ,g= 9.8 m/s²

The power P is given as

P= m g h

P=Power

m=Water flow rate

h=height

Now by putting the values in the above equation

P = 2.2 x 10⁶ x 9.8 x 65 W

P = 1401.4 x 10⁶ W

Therefore the power wasted will be 1401.4 x 10⁶ W.

7 0
3 years ago
Two semiconductors are identical except that one has a band gap of 1.2 eV, while the other has a band gap of 1.1 eV. The room te
solong [7]

To solve this problem it is necessary to apply the relationship given by the intrinsic carrier concentration, in each of the phases.

The intrinsic carrier concentration is the number of electrons in the conduction band or the number of holes in the valence band in intrinsic material. This number of carriers depends on the band gap of the material and on the temperature of the material.

In general, this can be written mathematically as

\eta_i = \sqrt{N_cN_v}e^{-\frac{E_g}{2KT}}

Both are identical semiconductor but the difference is band gap which is:

E_{g1} = 1.1eV

n_{i1} = 1*10^{19}m^{-3}

E_{g2} = 1.2eV

T=300K

The ratio between the two phases are given as:

\frac{\eta_{i1}}{\eta_{i2}} = \frac{e^{-\frac{E_{g1}}{2KT}}}{e^{-\frac{E_{g2}}{2KT}}}

\frac{\eta_{i1}}{\eta_{i2}} = e^{\frac{E_{g2}-E_{g1}}{2KT}}

\frac{\eta_{i1}}{\eta_{i2}} =e^{\frac{(1.2-1.1)(1.6*10^{-19})}{2(1.38*10^{-23})(300)}}

\frac{\eta_{i1}}{\eta_{i2}} =e^{-1.932367}

\frac{\eta_{i1}}{\eta_{i2}} =0.145

Therefore the ratio of intrinsic carrier densities for the two materials at room temperature is 0.145

7 0
4 years ago
Other questions:
  • Suppose it was discovered that Hubble's constant, H0, was smaller than previously thought. How would this affect our estimate of
    5·1 answer
  • A trained attack octopus can crawl at a velocity of 0.3m/s. If the octopus crawls towards its victim for 30 seconds, what is the
    11·1 answer
  • Which system allows for the movement of blood throughout the body? A. endocrine B. reproductive C. respiratory D. circulatory
    6·2 answers
  • Ron is a 30 year old male with wider hips and a short neck. He tends to have a have trouble with
    7·1 answer
  • A child and sled with a combined mass of 50.2 kg slide down a frictionless hill that is 8.38 m high. If the sled starts from res
    9·1 answer
  • 1. A roller coaster car rapidly picks up speed as it rolls down a slope. As it
    14·1 answer
  • What vaciole-like strucyure break down and recycle cell parts
    10·1 answer
  • PLS HELP QUICK!!!!!!!!
    6·2 answers
  • if two men are trying to carry a wooden pole. if one of them is weaker than other, how can they carry the pole hence making smal
    9·1 answer
  • A hockey puck that has a mass of 0.170 kg travels with a speed of 42.0 m/s.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!