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vazorg [7]
3 years ago
13

What unit do we use for pressure

Physics
2 answers:
nikdorinn [45]3 years ago
6 0

Answer:

ur answer is pascal (pa)

Explanation:

-Dominant- [34]3 years ago
5 0

Answer:

Pascal

Explanation:

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At a certain instant, a rotating turbine wheel of radius RR has angular speed ωω (measured in rad/srad/s). What must be the magn
jonny [76]

Answer:

Explanation:

The magnitude of the acceleration makes an angle of 30° with the tangential velocity.

Resolving the acceleration to tangential and radial acceleration

at = aCos30 = √3a/2

ar = aSin30 = ½a

a = 2•ar

Then, the tangential acceleration is the linear acceleration, so the relationship between the tangential acceleration and angular acceleration is given as:

at = Rα

Then, α = at/R

since at = √3a/2

Then, α = √3 at/2R, equation 1

The radial acceleration is given as

ar = ω²R

Note that, at² + ar² = a²

at = √(a²-ar²)

Back to equation 1

α = √3 at/2R

α = √3√(a²-ar²)/2R

α = √3√(a²-(w²R)²)/2R

α = √3(a²-w⁴R²) / 2R

Also, a = 2•ar = 2w²R

Then,

α = √3((2w²R)²-w⁴R²) / 2R

α = √3(4w⁴R²-w⁴R²) / 2R

α = √3(3w⁴R²) / 2R

α = √9w⁴R² / 2R

α = 3w²R / 2R

α = 3w²/2

7 0
3 years ago
What happens to a light if the switch is turned off in the circuit?
lukranit [14]

In a parallel circuit nothing happens. All the other lights stay on but if it was a series circuit ALL the lights would turn off at one time.

If there is an ABCD question I can answer that but I wasn't sure so I just said this

Hope it is helpful :)

6 0
3 years ago
How to classify an inner planet vs. outer planet
zvonat [6]
Outer planets are farther away and made up of gases. Inner planets closer. It's pretty much self explanatory. Hope this helps.
7 0
4 years ago
What are the types of energies released when a candle burns?
Phantasy [73]
When a candle is burning the candle is releasing thermal and radiant energy
4 0
4 years ago
Read 2 more answers
A ball of mass 4.5 kg moving with speed of 2.2 m/s in the +x-direction hits a wall and bounces back with the same speed in the x
Levart [38]

Answer:

The change of the momentum of the ball is -19.8\, \frac{mkg}{s}

Explanation:

We should find \varDelta\overrightarrow{p}=\overrightarrow{p_{f}}-\overrightarrow{p_{i}} (1)with \overrightarrow{p_{i}} the initial momentum and \overrightarrow{p_{f}} the final momentum. Linear momentum is defined as \overrightarrow{p}=m\overrightarrow{v}, using that on (1):

\varDelta\overrightarrow{p}=m \overrightarrow{v_{f}}-m \overrightarrow{v_{i}} (2)

It's important to note that momentum and velocity are vectors and direction matters, so if +x direction is the direction towards the wall and the -x direction away the wall \overrightarrow{v_{i}}=+2.2\, \frac{m}{s} and \overrightarrow{v_{f}}=-2.2\, \frac{m}{s} so (2) becomes:

\varDelta\overrightarrow{p}=m(-2.2- (+2.2))=-(4.5)(4.4)

\varDelta\overrightarrow{p}=-19.8\, \frac{mkg}{s}

8 0
4 years ago
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