Answer:
|x − 40| ≤ 7.5.
Step-by-step explanation:
The absolute value inequality |x − 40| ≤ y models the relationship between the acceptable weights of the suitcase and the amount it can vary.
If the suitcase weight can vary up to 7.5 pounds, then 7.5 can be substituted for y in the inequality:
|x − 40| ≤ 7.5.
This inequality can be used to find the range of acceptable weights of the suitcase.
One way is to divide 500 by 0.15
500/0.15=3333.3333333
the answer is about 3333 times
Ans: Option A
Explanation:Let's solve it smartly!
Given expression:
![x^{2} + bx +c](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%2B%20bx%20%2Bc)
--- (A)
Factors: (x+p)(x+q)
Condition: c<0
Now let us expand (x+p)(x+q):
=>
![x^{2} + (p+q)x + pq](https://tex.z-dn.net/?f=%20x%5E%7B2%7D%20%2B%20%28p%2Bq%29x%20%2B%20pq)
--- (B)
By comparing (B) with (A), we can say that:
pq = c --- (C)
Now, as the condition says,
c<0, it means either p or q is negative. Both cannot be positive or both cannot be negative.
1) If p>0, q>0, it means c>0 since (+p)(+q) = (+c)(according to equation (C)). Condition is not met.
Hence, option B and D are wrong.
2) If p<0, q<0 it means c>=0 since (-p)(-q) = (+c)(according to equation (C)). Condition is not met.
Hence option C is out as well.
We are left with Option A:
p<0, q>0 it means c<0 since (-p)(+q) = (-c)(according to equation (C)). Condition is MET!
Hence,
Ans: Option A: p= -3, q= 7
The first step to solve this is to move the constant to the right side of the expression and change its sign
3x > 3 - 2.4
Subtract the numbers on the right side of the expression
3x > 0.6
Lastly,, divide both sides of the inequality by 3 to get your final answer.
x > 0.2
This means that the correct answer to your question is x > 0.2.
Let me know if you have any further questions
:)
Answer:
10/3 minutes
Step-by-step explanation:
12 minutes to run 6 times is the same as 2 minutes to run once (ratios)
so it takes 2 minutes to run once around a 600 m track
so 2 minutes/600m = x minutes/1000m
x = 2/600 * 1000 = 20/6 = 10/3