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WARRIOR [948]
3 years ago
12

Find the midpoint between each pair of point 15. (-1,-5) and (-5, 7) 16. (5,-2) and (-4, 2)

Mathematics
1 answer:
n200080 [17]3 years ago
4 0

Answer:

Midpoint of (-1,-5) and (-5,7) is (-3,1)

Midpoint of (5,-2) and (-4,2) is (0.5,0)

Step-by-step explanation:

Use the midpoint formula

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What is the average rate of change of the function from x = 0 to x = 2?.
irina1246 [14]

The average rate of change of the function from x = 0 to x = 2 is -2

From the complete question (see attachment), we have the following ordered pair when x = 0 and x = 2

(x,y) = \{(0,10)\ (2,6)\}

The average rate of change is calculated using:

\Delta x = \frac{y_2 -y_1}{x_2 -x_1}

So, we have:

\Delta x = \frac{6-10}{2-0}

Evaluate common terms

\Delta x = \frac{-4}{2}

Divide -4 by 2

\Delta x = -2

Hence, the average rate of change of the function from x = 0 to x = 2 is -2

Read more about rate of change at:

brainly.com/question/8728504

5 0
3 years ago
Is X=3 calculate the value of X3+X btw the 3 is a small three
Naddik [55]
The only 'small number' that I know that would affect the answer is an exponent that looks like ³ so the problem would be x³+x

remember that x³=x times x times x
if x=3 then
3³+3=27+3=30
3 0
3 years ago
Read 2 more answers
X=<br> Length=<br> Width=<br> WILL GIVE BRAINLIEST + 5 star
babymother [125]

Answer:

x = 20

Length = 20ft

Width = 12ft

Step-by-step explanation:

A = 240

x^2 - 8x = 240

x^2 - 8x - 240 = 0

x^2 - 20x + 12x - 240 = 0

x(x-20) + 12(x-20) = 0

(x+12)(x-20) = 0

x = 20

x = -12 (which we discard since x is a length)

So the dimensions are 20ft and 20-8 = 12ft

7 0
3 years ago
The surface area of this rectangular prism of 5m,5m,4m
Blizzard [7]

Answer:

130 m^2 (meters squared)

4 0
2 years ago
Weights were recorded for all nurses at a particular hospital, the mean weight for an individual nurse was 135 lbs. with a stand
Aloiza [94]
Given:
population mean, &mu; =135
population standard deviation, &sigma; = 15
sample size, n = 19

Assume a large population, say > 100,
we can reasonably assume a normal distribution, and a relatively small sample.
The use of the generally simpler formula is justified.

Estimate of sample mean
\bar{x}=\mu=135

Estimate of sample standard deviation
\s=\sqrt{\frac{\sigma^2}{n}}
=\sqrt{\frac{15^2}{19}}=3.44124  to 5 decimal places.

Thus, using the normal probability table,
P(125
=P(\frac{125-135}{3.44124}
=P(-2.90593
=P(Z
=P(Z

Therefore 
The probability that the mean weight is between 125 and 130 lbs 
P(125<X<130)=0.0731166-0.0018308
=0.0712858



3 0
3 years ago
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