The height of the triangular base of the pyramid is calculated through the equation,
h = (cos x)(18 in)
where h is height and x is half of the angle of the triangle. Since the triangle is equilateral, the value of x is 30°. Substituting,
h = (cos 30°)(18 in)
h = 15.59 in
Thus, the height of the base is approximately 15.59 inches.
Answer:
x = 4
Step-by-step explanation:
Since JB is the bisector of AD and the length of AD is given as 24 we can conclude that AZ is 12 (half of AD)
2x + 4 = 12
2x = 8
x = 4
Well, 5384 is 5000 bigger than 384. So you would add 20000 (4*5000) to the answer of 4*384, which is 1536.
So 1536+20000=21536
2. Each side of a pentagon is the same size.
4cm x 5 = 20cm or 4cm+4cm+4cm+4cm+4cm = 20cm
3. Each side of a square is the same size.
13yd x 4 = 52yd or 13yd+13yd+13yd+13yd = 52yd
4. Add all sides together.
12m+12m+30m+30m = 84m
5. Again add all sides together.
16yd+16yd+4yd+4yd = 40yd
6. Each side of a square is the same size.
7in x 4 = 28in. or 7in+7in+7in+7in = 28in
7. Add all sides together.
2cm+2cm+3cm+3cm = 10cm
8. Each side of a rhombus is the same size. A rhombus has 4 sides.
23in x 4 = 92in or 23in+23in+23in+23in = 92in
9. A regular octagon has 8 sides and each side is the same size.
9cm x 8 = 72cm
Hello!
1. 8y = 48 => y = 48 : 8 => y = 6
2. q - 12 = 1 => q = 1 + 12 => q = 13
3. 18 = a/2 => a = 18 × 2 => a = 36
4. r/3 = 7 => r = 3 × 7 => r = 21
5. 11 = m - 4 => m = 11 + 4 => m = 15
Good luck! :)
