A set of data has a normal distribution with a mean of 5.1 and a standard deviation of 0.9. Find the percent of data between 4.2 and 5.1.
Answer: The correct option is B) about 34%
Proof:
We have to find 
To find
, we need to use z score formula:
When x = 4.2, we have:


When x = 5.1, we have:


Therefore, we have to find 
Using the standard normal table, we have:
= 

or 34.13%
= 34% approximately
Therefore, the percent of data between 4.2 and 5.1 is about 34%
Answer: it’s not an even number it 6.6 repeating so if round up and say 7 bags
Step-by-step explanation:
Answer: X= 4
Step-by-step explanation:
24+0.44x=19+1.69x exp equation like:
24+44x/100=19+169x/100
Multiply left and right side of equation with 100
2400+44x=1900+169x
2400-1900=169x-44x
500=125x
x=500/125
x=4
Answer: 13
Step-by-step explanation: All you have to do is subtract -12 from -25 and you get -13. If it was -25 from 12 you would just add the two together.