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MakcuM [25]
3 years ago
12

Help? don't know what to pick, and please dont choose randomly

Mathematics
2 answers:
Yakvenalex [24]3 years ago
6 0

Answer:

yess!!!

step-by-step explained.

......

IgorLugansk [536]3 years ago
4 0
Yes because since its showing the box of the 90° angle, it shows the same size and shape of the triangle (but of course one of em is flipped) and thats pretty much, so yes is your answer! Hope it helped!
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Order from least to greatest<br> 45<br> 11, 45, 520, 54
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Answer: 11, 45, 45, 54, 520

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One of the psychologist's findings is that 18 months after the workshop, a sample of 49 job seekers who received training on set
IceJOKER [234]

Answer:

The psychologist finds that the estimated Cohen's d is 0.583.

Step-by-step explanation:

The Cohen's d is used to calculate the effect size, appied when a null hypothesis is rejected.

It can be calculated for this case of population mean as:

d=\dfrac{M-\mu}{\sigma}=\dfrac{6.5-5.8}{1.2}=\dfrac{0.7}{1.2}=0.583

The psychologist finds that the estimated Cohen's d is 0.583.

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3 years ago
A tank in the shape of an inverted right circular cone has height 7 meters and radius 2 meters. It is filled with 5 meters of ho
iren [92.7K]

Answer:

The work required to empty the tank is 1,580,887 J

Step-by-step explanation:

Work = mass of chocolate × acceleration due to gravity × height of chocolate

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height of chocolate = 5 m

Work = 32,263×9.8×5 = 1,580,887 J

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2 years ago
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Which inequality can be used to represent this problem? (HELP ASAP, IM TIMED)
Nadya [2.5K]

Propane costs $3.50 per hundred pounds,

and there is a $6 monthly delivery fee.  

A family has budgeted $85 for their propane this month.

Let  'x' hundreds of pounds can the family use without going over budget

Here family has budgeted $85 for their propane.

So the cost for Propane  = $ 3.5x

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Therefore cost + delivery charge not exceed $85

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8 0
2 years ago
Help i dont understand how to complete this
Luda [366]

Answer: Josh = 19.8 hours, Danny = 10.8 hours

<u>Step-by-step explanation:</u>

Josh: \dfrac{1}{x+9}\\\\\\Danny: \dfrac{1}{x}\\\\\\Together: \dfrac{1}{7}\\\\\\Josh\quad + \quad Danny\quad =\quad Together\\\dfrac{1}{x+9}\quad +\qquad \dfrac{1}{x}\qquad = \qquad \dfrac{1}{7}\\\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (x+9)(x)(7)}}\\\\7(x) + 7(x+9)=x(x+9)\\7x + 7x + 63 = x^2+9x\\14x+63=x^2+9x\\0=x^2-5x-63\\\\\\\underline{\text{Use the quadratic formula to solve for x: }}x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}

x=\dfrac{-(-5)\pm \sqrt{(-5)^2-4(1)(-63)}}{2(1)}\\\\\\.\quad =\dfrac{5\pm\sqrt{25+252}}{2}\\\\\\.\quad =\dfrac{5\pm\sqrt{277}}{2}\\\\\\.\quad =\dfrac{5\pm 16.6}{2}\\\\\\x =\dfrac{5+16.6}{2}\qquad x=\dfrac{5-16.6}{2}\\\\\\x=\dfrac{21.6}{2}\qquad \qquad x=\dfrac{-11.6}{2}\\\\\\x=10.8 \qquad \qquad x=-5.8

Since time cannot be negative, x=-5.8 is an extraneous solution (not valid) so x = 10.8

Josh: x + 9   -->   10.8 + 9   =   19.8

Danny: x     -->    10.8

****************************************************************************************

2a) k = 9.45 & 0.55

2b) x = 3/2

2c) x = 2/3     <em>(x = -1 is an extraneous solution so is not valid)</em>

2d) No Solution   <em>(x = 1 is an extraneous solution so is not valid)</em>

Here is the work for 2a.  Follow this format for b, c, & d

\dfrac{3}{k^2-8x+12}=\dfrac{k}{k-2}-\dfrac{4}{k-6}\\\\\text{Since the denominator cannot equal zero, then } k \neq2\ and\ k\neq6\\\text{If either of the solutions are 2 or 6, then that solution needs to be crossed out}\\\\\underline{\text{Clear the denominator by multiplying by the LCM: (k-2)(k-6)}}\\\\3 = k(k-6)-4(k-2)\\3=k^2-6k-4k+8\\0=k^2-10k+5\\\\\\\underline{\text{Use the quadratic formula to solve for k}}

x=\dfrac{-(-10)\pm \sqrt{(-10)^2-4(1)(5)}}{2(1)}\\\\\\.\quad =\dfrac{10\pm\sqrt{100-20}}{2}\\\\\\.\quad =\dfrac{10\pm\sqrt{80}}{2}\\\\\\.\quad =\dfrac{10\pm8.9}{2}\\\\\\x=\dfrac{10+8.9}{2}\qquad x=\dfrac{10-8.9}{2}\\\\\\x=\dfrac{18.9}{2}\qquad x=\dfrac{1.1}{2}\\\\\\x=9.45\qquad x=0.55\\\\\\\text{Both answers are valid!}

8 0
3 years ago
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