Answer:
0.347% of the total tires will be rejected as underweight.
Step-by-step explanation:
For a standard normal distribution, (with mean 0 and standard deviation 1), the lower and upper quartiles are located at -0.67448 and +0.67448 respectively. Thus the interquartile range (IQR) is 1.34896.
And the manager decides to reject a tire as underweight if it falls more than 1.5 interquartile ranges below the lower quartile of the specified shipment of tires.
1.5 of the Interquartile range = 1.5 × 1.34896 = 2.02344
1.5 of the interquartile range below the lower quartile = (lower quartile) - (1.5 of Interquartile range) = -0.67448 - 2.02344 = -2.69792
The proportion of tires that will fall 1.5 of the interquartile range below the lower quartile = P(x < -2.69792) ≈ P(x < -2.70)
Using data from the normal distribution table
P(x < -2.70) = 0.00347 = 0.347% of the total tires will be rejected as underweight
Hope this Helps!!!
Answer:-2
Step-by-step explanation:
Log3(1/9)
Log(1/9) ➗ Log3
Log(1/3^2) ➗ Log3
Log3^(-2) ➗ Log3
-2Log3 ➗ Log3
-2(Log3 ➗ Log3)
-2
Answer:
y + 9 = -0.4(x-7)
Step-by-step explanation:
in slope form , we will use y - y1 =m ( x - x1) ,
which will be y + 9 = -2/5(x-7) ,
in reduced form , we have y + 9 = -0.4(x-7)
Answer:
we need to see the picture or diagram that corresponds to these problems
Step-by-step explanation:
I cant help you unless I see the picture/diagram that corresponds to these problems
