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3 years ago

#11 and #12 please explain so I can get it

Mathematics

1 answer:

Nat2105 [25]3 years ago

6 0

That's for number 11

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Find the slope of the line.

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The slope of the line is 1/2

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3 years ago

The floor tiles In the Jackson family kitchen are squares that measure 8 and 3/4 to a side. Each grid Square in the drawing meas

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Step-by-step explanation:

1inch=35 inch

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3 years ago

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Is 1/3, 2/3, 4/3, 8/3, 16/3 arithmetic sequence

11111nata11111 [884]

The given sequence is not arithmetic sequence

Solution:

Given sequence is:

$\frac{1}{3} , \frac{2}{3} , \frac{4}{3} , \frac{8}{3} , \frac{16}{3}$

We have to find if the above sequence is arithmetic sequence or not

An arithmetic sequence is a sequence of numbers such that the difference of any two successive members of the sequence is a constant

Here in the given sequence

$\text{ first term } = a_1 = \frac{1}{3}\\\\\text{ second term } = a_2 = \frac{2}{3}\\\\\text{ third term } = a_3 = \frac{4}{3}\\\\\text{ fourth term } = a_4 = \frac{8}{3}\\\\\text{ fifth term } = a_5 = \frac{16}{3}$

Let us find the difference between terms

$a_2 - a_1 = \frac{2}{3} - \frac{1}{3} = \frac{1}{3}$

$a_3 - a_2 = \frac{4}{3} - \frac{2}{3} = \frac{2}{3}$

$a_4 - a_3 = \frac{8}{3} - \frac{4}{3} = \frac{4}{3}$

$a_5 - a_4 = \frac{16}{3} - \frac{8}{3} = \frac{8}{3}$

Thus the difference between terms is not constant

So the given sequence is not arithmetic sequence

5 0

3 years ago

Please Help! I don't know how to do this! (3x^2+7x-4)-(6x^2-6x+1)

antoniya [11.8K]

Answer:

-3x^2+13x-5

Step-by-step explanation:

you're basically just combining the like terms

3x^2+7x-4-6x^2+6x-1

-3x^2=13x-4-1

-3x^2+13x-5

8 0

3 years ago

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Please help asap!!!!!!

mr Goodwill [35]

<h2>Hello!</h2>

The answer is:

The difference between the areas of the circles will be:

$Difference=36\pi -9\pi =27\pi$

To find the diffence in area between the two circles, we need to find both areas and then, subtract the smallest circle area to the largest circle area.

So,

For the small circle, we have:

$Area_{SmallCircle}=\pi *radius^{2} \\\\Area_{SmallCircle}=\pi *(3)^{2}=9\pi$

For the large circle, we have:

$Area_{LargeCircle}=\pi *radius^{2} \\\\Area_{LargeCircle}=\pi *(6)^{2}=36\pi$

Hence, we have that the difference between the areas of the circles will be:

$Difference=36\pi -9\pi =27\pi$

Have a nice day!

3 0

4 years ago

Read 2 more answers