Given the following m(x)=5x-3
1 answer:
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The Answer is x=7, y=6
Solve the following system:
{14 x - 4 y = 74 | (equation 1)
{7 x - 7 y = 7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{14 x - 4 y = 74 | (equation 1)
{0 x - 5 y = -30 | (equation 2)
Divide equation 1 by 2:
{7 x - 2 y = 37 | (equation 1)
{0 x - 5 y = -30 | (equation 2)
Divide equation 2 by -5:
{7 x - 2 y = 37 | (equation 1)
{0 x+y = 6 | (equation 2)
Add 2 × (equation 2) to equation 1:
{7 x+0 y = 49 | (equation 1)
{0 x+y = 6 | (equation 2)
Divide equation 1 by 7:
{x+0 y = 7 | (equation 1)
{0 x+y = 6 | (equation 2)
Collect results:
Answer: {x = 7
{y = 6
P{lease note the brackets are supposed to go over both equations but I haven'y been able to find a way to make it work, see attachment.
Solve the following system:
{14 x - 4 y = 74 | (equation 1)
{7 x - 7 y = 7 | (equation 2)
Subtract 1/2 × (equation 1) from equation 2:
{14 x - 4 y = 74 | (equation 1)
{0 x - 5 y = -30 | (equation 2)
Divide equation 1 by 2:
{7 x - 2 y = 37 | (equation 1)
{0 x - 5 y = -30 | (equation 2)
Divide equation 2 by -5:
{7 x - 2 y = 37 | (equation 1)
{0 x+y = 6 | (equation 2)
Add 2 × (equation 2) to equation 1:
{7 x+0 y = 49 | (equation 1)
{0 x+y = 6 | (equation 2)
Divide equation 1 by 7:
{x+0 y = 7 | (equation 1)
{0 x+y = 6 | (equation 2)
Collect results:
Answer: {x = 7
{y = 6
P{lease note the brackets are supposed to go over both equations but I haven'y been able to find a way to make it work, see attachment.