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netineya [11]
3 years ago
6

Extending the Number System Unit Test ansers

Mathematics
2 answers:
skelet666 [1.2K]3 years ago
5 0

Answer:

Please add a picture

Step-by-step explanation:

Snezhnost [94]3 years ago
5 0

Answer:

are you giving the answer away?

Step-by-step explanation:

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What is the ratio of a:b, knowing that a-b/a+b = 3/5.
ser-zykov [4K]

Answer:

4:1

Step-by-step explanation:

\frac{a-b}{a+b} = \frac{3}{5}

4-1 = 3

4+1 = 5

5 0
3 years ago
185g in the ratio 2:3
Thepotemich [5.8K]

\\Find total parts:

2 + 3 = 5


\\ FInd 1 part:

185 ÷ 5 = 37


\\Find 2 parts:

37 x 2 = 74


\\Find 3 parts:

37 x 3 = 111


2: 3 = 74g : 111g


Answer: 74g : 111g

3 0
3 years ago
A cantaloupe weighs 1/2. A watermelon weighs four times as much as the cantaloupe, how much does the watermelon weighs?
mars1129 [50]

Answer:2

Step-by-step explanation: 1/2=0.5   0.5x4=2

5 0
3 years ago
Read 2 more answers
(All problems are connected with eachother.) Directions: Mr. Clark's backyard vegetable garden is circular, centered at point A,
jonny [76]
Check the picture below. part 1 and 2 are there.

part 3)

\bf \textit{arc's length}\\\\
s=\cfrac{r\theta \pi }{180}\implies \cfrac{180s}{r\pi }=\theta \qquad 
\begin{cases}
\theta =\textit{angle in degrees}\\
r=radius\\
----------\\
s=12.2\\
r=\sqrt{\frac{315}{\pi }}
\end{cases}
\\\\\\
\cfrac{180\cdot 12.2}{\pi \sqrt{\frac{315}{\pi }}}=\theta \implies 69.8075^o\approx \theta \implies 70^o\approx\theta

\bf \textit{area of a sector of a circle}\\\\
A=\cfrac{\theta \pi r^2}{360}\quad 
\begin{cases}
r=\sqrt{\frac{315}{\pi }}\approx 10\\
\theta \approx 70
\end{cases}\implies A=\cfrac{70\cdot \pi \cdot 10^2}{360}

4 0
3 years ago
Find an equation for the line that passes through the points , −4−5 and , 2,5 .
Ronch [10]

Answer:

5x -3y = -5

Step-by-step explanation:

One formula that is useful for writing equations of lines through two points is ...

... (x2 -x1)(y -y1) = (y2 -y1)(x -x1)

Using the given points, this becomes ...

... (2 -(-4))(y -(-5)) = (5 -(-5))(x -(-4))

... 6(y +5) = 10(x +4) . . . . simpify

We can divide by 2 and subtract the left side to get ...

... 0 = 5x +20 -3y -15

... 0 = 5x -3y +5 . . . . . . . this is the <em>general form</em> equation of a line

Subtracting the constant gives the <em>standard form</em> equation.

... 5x -3y = -5

_____

<em>Comment on the solution</em>

As a rule, writing the equation this way from integer coefficients avoids fractions entirely. In the form with x on one side and y on the other, you can choose to move the x-term or leave it be, in order to ensure that it has a positive coefficient in the final equation. (Here we left it alone and moved the y-term.)

The standard form requires that the numbers in the equation be relatively prime (no common factors). That is why we divided by the common factor 2 in the development above.

4 0
4 years ago
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