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earnstyle [38]
3 years ago
12

Find all solutions to the equation. cos2x + 2 cos x + 1 = 0

Mathematics
1 answer:
yanalaym [24]3 years ago
5 0
For cos(2x) * (2cos(x) + 1) = 0, use the double angle identity for cos(2x), which is cos^2 x - sin^2 x = cos^2 x - (1-cos^2) = 2cos^2 x - 1.
So we have (2cos^2 x - 1)(2cos x + 1) = 0. So 2cos^2 x -1 = 0 or x = 0 and 2pi.
For 2sec^2 x + tan^2 x - 3 = 0, use the identity sec^2 x = tan^2 x + 1, so we have
2(tan^2 x + 1) + tan^2 x - 3 = 0 or
<span>2tan^2 x + tan^2 x - 1 = 0 or
</span>3 tan^2 x = 1.

So x = pi/2, pi/2 + pi = 3pi/2.

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The temperature in Montreal was -8°C
atroni [7]

Answer:

id say  about 19 degrees

Step-by-step explanation:

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3 years ago
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Note: Enter your answer and show all the steps that you use to solve this problem in the space provided.
nika2105 [10]

Step-by-step explanation:

13 + 22 = 35 degree change. 10-3 = 7. 35/7 = 5 degrees per hour.

4 0
3 years ago
(08.07 HC)
andreev551 [17]

Answer:

\textsf{A)} \quad x=-2, \:\:x=\dfrac{5}{2}

\textsf{B)} \quad \left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

C)  See attachment.

Step-by-step explanation:

Given function:

f(x)=2x^2-x-10

<h3><u>Part A</u></h3>

To factor a <u>quadratic</u> in the form  ax^2+bx+c<em> , </em>find two numbers that multiply to ac and sum to b :

\implies ac=2 \cdot -10=-20

\implies b=-1

Therefore, the two numbers are -5 and 4.

Rewrite b as the sum of these two numbers:

\implies f(x)=2x^2-5x+4x-10

Factor the first two terms and the last two terms separately:

\implies f(x)=x(2x-5)+2(2x-5)

Factor out the common term  (2x - 5):

\implies f(x)=(x+2)(2x-5)

The x-intercepts are when the curve crosses the x-axis, so when y = 0:

\implies (x+2)(2x-5)=0

Therefore:

\implies (x+2)=0 \implies x=-2

\implies (2x-5)=0 \implies x=\dfrac{5}{2}

So the x-intercepts are:

x=-2, \:\:x=\dfrac{5}{2}

<h3><u>Part B</u></h3>

The x-value of the vertex is:

\implies x=\dfrac{-b}{2a}

Therefore, the x-value of the vertex of the given function is:

\implies x=\dfrac{-(-1)}{2(2)}=\dfrac{1}{4}

To find the y-value of the vertex, substitute the found value of x into the function:

\implies f\left(\dfrac{1}{4}\right)=2\left(\dfrac{1}{4}\right)^2-\left(\dfrac{1}{4}\right)-10=-\dfrac{81}{8}

Therefore, the vertex of the function is:

\left(\dfrac{1}{4},-\dfrac{81}{8}\right)=(0.25,-10.125)

<h3><u>Part C</u></h3>

Plot the x-intercepts found in Part A.

Plot the vertex found in Part B.

As the <u>leading coefficient</u> of the function is positive, the parabola will open upwards.  This is confirmed as the vertex is a minimum point.

The axis of symmetry is the <u>x-value</u> of the <u>vertex</u>.  Draw a line at x = ¹/₄ and use this to ensure the drawing of the parabola is <u>symmetrical</u>.

Draw a upwards opening parabola that has a minimum point at the vertex and that passes through the x-intercepts (see attachment).

5 0
2 years ago
Which of the following is the ratio of 5 cm to 10 km​
pshichka [43]

Answer:

1/200000

Step-by-step explanation:

first 10 km equals to 1000000cm

so 5/1000000cm

equals to 1/200000

3 0
2 years ago
Esmeralda received a bag of jellybeans that contained a mixture of regular flavored jellybeans and "surprise" jellybeans. The ba
Firlakuza [10]

Answer:

6  "surprise" flavors jellybeans

Step-by-step explanation:

From the information given:

The bag contained a mixture of regular flavored jellybeans and "surprise" jellybeans.

There are 40 jellybeans in the bag.

If 15% of the jellybean were "surprise" flavors.

Then, the number of expected "surprise" jellybeans will be:

= 15% of 40 jellybeans

= (15/100) × 40

= 6  "surprise" flavors jellybeans

If  6 surprise jellybean is contained in the bag;

Thus, the number of regular flavored jellybean will be

= 40 - 6

= 34 regular flavored jellybean

5 0
2 years ago
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