Factor the expression.
3(128j+3)
Answer:
0.30
Step-by-step explanation:
Probability of stopping at first signal = 0.36 ;
P(stop 1) = P(x) = 0.36
Probability of stopping at second signal = 0.54;
P(stop 2) = P(y) = 0.54
Probability of stopping at atleast one of the two signals:
P(x U y) = 0.6
Stopping at both signals :
P(xny) = p(x) + p(y) - p(xUy)
P(xny) = 0.36 + 0.54 - 0.6
P(xny) = 0.3
Stopping at x but not y
P(x n y') = P(x) - P(xny) = 0.36 - 0.3 = 0.06
Stopping at y but not x
P(y n x') = P(y) - P(xny) = 0.54 - 0.3 = 0.24
Probability of stopping at exactly 1 signal :
P(x n y') or P(y n x') = 0.06 + 0.24 = 0.30
Answer:
Probability (bid accepted) = 0.48
Step-by-step explanation:
Probability density is given byF(y)= 1/(b-a)
a=9500
b= 14700
F(y)= 1/(14700-9500) =1/5200=0.00019
Probability (bid accepted)= (12000-9500)÷1/5200
P( bid accepted) = 2500×0.00019=0.475 approximately 0.48
We are given
P = <span>$1,945.61
r = 11.2%
Amin = $156
A = $300
First, we convert the interest to effective monthly terms
i = 11.2%/12 = 0.933%
After one month, the interest saved by paying more than the minimum is
</span>(0.00933) (300 - 156) = $1.35
To do this multiply 1 by 4, then 3 by 5. 4 over 15 is your answer.
