Question

Can you help me with this problem please

Answer 1

Remark

I think you want us to do both 3 and 4

Three

QR is 4 points going left from the y axis + 2 points going right from the y axis.

QR = 6 units long.

RT is 4 units above the x axis and 3 units below the x axis

RT = 7 units long

TS = 3 units. For this one you just go from T to S. The graph really helps you. You just need to count.

Problem 4

You need to find the area of the combined figure. You could do it as a trapezoid, which might be the easiest way. I'll do that first.

Area = (b1 + b2)*h/2

Givens

B1 = QR = 6

B2 = UT + TS = 6 + 3 = 9

h = RT = 7

Area

Area = (6 + 9)*7/2

Area = 15 * 7 / 2

Area = 52.5

Comment

You could break this up into a rectangle + a triangle

Find the area of QRTU and add the Area of triangle RTS

Area of the rectangle = L * W

L = RT = 7

W = QR = 6

Area = 7 *6 = 42

Area of the triangle = 1/2 * B * H

B = TS = 3

H = RT =7

Area = 1/2 * 3 * 7

Area = 1/2 * 21

Area = 10.5

Total Area = 42 + 10.5 = 52.5 Both answers agree.