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3 years ago

A set of 3 consecutive odd intergers sum to 249 what is the greatest interger

Mathematics

1 answer:

Yuliya22 [10]3 years ago

8 0

Answer:

Step-by-step explanation:

What id id was divide 249 by three, then add to two the number and subract two, then you could add the odd numbers you got each time to get 249.

249/3=83

83+2+85

83-2=81

81+83+85=249

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189,360 +22,857

givi [52]

Answer:

212,217

Step-by-step explanation:

189360+22857 = 212,217

5 0

1 year ago

What is the area of a circle whose diameter is 32 inches? Use π=3.14 in your calculations. Show your work.

Rina8888 [55]

R = 32 / 2 = 16
Pie = 3.14
Area of circle = pie x r^2
= 3.14 x 16^2 = 803.84

5 0

3 years ago

Which expression is equivalent to 15x^-3z^5/3x^7z^-5 please answer spr fast

Law Incorporation [45]

Answer:

$5x^{-10}z^{10$

Step-by-step explanation:

Given

$\frac{15x^{-3}z^5}{3x^7z^{-5}}$

Required

Evaluate

$\frac{15x^{-3}z^5}{3x^7z^{-5}}$

Start by dividing 15 by 3

$\frac{5x^{-3}z^5}{x^7z^{-5}}$

Apply the following law of indices on indices x and z

$\frac{a^m}{a^n} = a^{m-n$

So, the expression becomes:

$5x^{-3-7}z^{5-(-5)$

$5x^{-3-7}z^{5+5$

$5x^{-10}z^{10$

3 0

2 years ago

Read 2 more answers

Recursive formula of the arithmetic sequence 4,9,14,19

lukranit [14]

Answer:

4,9,14,19,24,29,34,39

4 0

1 year ago

$4000 is invested in a mutual fund that pays annual interest compounded quarterly for 15 years. What annual interest is needed t

Neporo4naja [7]

Answer:

The interest needed to reach that value of $6000 is 2.75%

Step-by-step explanation:

Given as :

The principal that invested in mutual fund = p = $4000

The time period = t = 15 years

The Amount after 15 years = A = $6000

Let The interest needed to reach that value = r%

Now, According to question

<u>From Compound Interest method</u>

Amount = principal × $(1+\dfrac{\textrm rate}{100})^{\textrm time}$

Or, A = p × $(1+\dfrac{\textrm r}{100})^{\textrm t}$

Or, $6000 = $4000 × $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, $\dfrac{6000}{4000}$ = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

Or, $\frac{3}{2}$ = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, 1.5 = $(1+\dfrac{\textrm r}{100})^{\textrm 15}$

or, $1.5^{\frac{1}{15}}$ = $(1+\dfrac{\textrm r}{100})$

or, 1.0275 = $(1+\dfrac{\textrm r}{100})$

or, 1.0275 - 1 = $\dfrac{r}{100}$

or, 0.0275 = $\dfrac{r}{100}$

∴ r = 0.0275 × 100

I.e r = 2.75

So, The interest needed to reach that value = r = 2.75%

Hence,The interest needed to reach that value of $6000 is 2.75% Answer

3 0

3 years ago