False because they don't have the same length and shape you know they may be triangle but the their length are different.
y = x^2 + 2x...eqn 1
y = 3x + 20...eqn 2
subst for y in eqn 1...
=> x^2 +2x = 3x +20
=> x^2 - x - 20 =0
=> (x-5) (x+4) =0
=> x = 5 or -4
for x =5, y = 35 (sub for x in eqn 1 or 2)
for x = -4, y = 8 (sub for x in eqn 1 or 2)
Answer:
The correct answer is 0 or A
Step-by-step explanation:
2/0+2 + 1/5 = 6/0+5
2/2 + 1/5 = 6/5
1 + 1/5 = 6/5
5/5 + 1/5 = 6/5
6/5 = 6/5
