Solve y3 = 125. a.y = 5 b.y = 25 c.y = 11.2 d. y = 15

A point P has coordinates (-8, -2). what are its new coordinates after reflecting point P across the y-axis?

just olya [345]

Answer:

(-8,2)

Step-by-step explanation:The y-value does not change, only the x-value becomes positive.

5 0

3 years ago

Roll the number cube to find the observed frequency. Which statements are true? Check all that apply

ch4aika [34]

Answer:

(a) and (c)

Step-by-step explanation:

Given

See attachment for complete question

Required

Select all true statements

First, calculate the total observed frequency;

$Total = 11 + 16 + 14 + 20 + 12 + 17$

$Total = 90$

(a): Relative frequency of 4 is 2/9

Relative frequency is calculated by:

$RF= \frac{Observed\ Frequency}{Total}$

For roll 4

$Observed\ frequency = 20$

So, the relative frequency is:

$RF = \frac{20}{90}$

Simplify

$RF = \frac{2}{9}$

(a) is true

(b): Experimental probability of 3 greater than its theoretical probability

The experimental probability is its relative frequency;

For roll 3

$Observed\ frequency = 14$

The experimental probability is:

$Pr = \frac{14}{90}$

Simplify

$Pr = \frac{7}{45} = 0.156$

To calculate the theoretical probability, w have:

$S = \{1,2,3,4,5,6\}$ ---- sample space

$n(S)= 6$

$n(3) = 1$ --- number of times 3 occur

The theoretical probability is:

$Pr = \frac{1}{6} = 0.167$

The theoretical probability is $greater\ than\ the$ experimental probability.

(b) is false

(c): Experimental probability of 2 greater than its theoretical probability

Using the explanations in (b), we have:

For roll 2

$Observed\ frequency = 16$

The experimental probability is:

$Pr = \frac{16}{90}$

Simplify

$Pr = \frac{8}{45} = 0.178$

To calculate the theoretical probability, we have:

$n(S)= 6$

$n(2) = 1$

The theoretical probability is:

$Pr = \frac{1}{6} = 0.167$

The experimental probability is $greater\ than\ the$ theoretical probability.

(c) is true

(d): Relative frequency of 5 is 2/13

For roll 5

$Observed\ frequency = 12$

The relative frequency is:

$RF = \frac{12}{90}$

Simplify

$RF = \frac{2}{15}$

(d) is true

7 0

2 years ago

A cooling tower for a nuclear reactor is to be constructed in the shape of a hyperboloid of one sheet. The diameter at the base

timurjin [86]

Answer:

Step-by-step explanation:

Equation for a hyperboloid of one sheet, with center at the origen and axis along z-axis is:

(x/a)² + (y/b)² - (z/c)² = 1 (1)

We have to find a , b, and c

We can express equation (1)

(x/a)² + (y/b)² = (z/c)² + 1 (2)

Now if we cut the hyperboloid with planes parallel to xy plane we get for z = k ( K = 1 , 2 , 3 and so on ) circles of different radius

(x/a)² + (y/b)² = (k/c)² + 1

at z = k = 0 at the base of the hyperboloid d = 300 or r = 150 m

we have

(x/a)² + (y/b)² = 1

x² + y² = a² a² = (150)² a = b = 150

and x² + y² = (150)²

Now the other condition is at 200 m above the base d = 500 m r = 250 m minimum diameter then in equation (2) we have:

(x/a)² + (y/b)² = (z/c)² + 1

(1/a)² [ x² + y² ] = (z/c)² + 1

but x² + y² = r² and in this case r = 250 m then

(250)²/(150)² = (z/c)² + 1 ⇒ (62500/ 22500) = (200/c)² + 1

2,78 = 40000/c² + 1

2.78c² = 40000 + c²

1.78c² = 40000

c² = 40000/1.78

c² = 22471.91

c = 149,91

Then we finally have the equation:

x²/(150)² + y² /(150)² - z²/149,91 = 1

7 0

3 years ago

Given that 2x-7y=30

lidiya [134]

Answer:

y = - $\frac{24}{7}$

Step-by-step explanation:

Substitute x = - 3 into the expression

2x - 7y = 30

2(- 3) - 7y = 30

- 6 - 7y = 30 ( add 6 to both sides )

- 7y = 36 ( divide both sides by - 7 )

y = $\frac{36}{-7}$ = - $\frac{36}{7}$

4 0

2 years ago

Jarvis began operations on January 1, Year 1 with an owner investment of $12,400. There have been no additional owner investment

anygoal [31]

(a) The statement of owner's equity for Year 1 is $26,920

(b) The statement of owner's equity for Year 2 is $52,720

(a) Preparation of the statement of owner's equity for Year 1 at its December 31 year end.

JARVIS statement of owner's equity for year ended December 31 Year 1

Owner investment $12,400

Add Net income $ 33,600

Less Jarvis, Withdrawals ($ 19,080)

Statement of owner's equity for Year 1 $26,920

(b) Preparation of the statement of owner's equity for Year 2 at its December 31 year end.

JARVIS statement of owner's equity for year ended December 31 Year 2

Owner investment $12,400

Add Net income $ 56,000

Less Jarvis, Withdrawals $ 15,680

Statement of owner's equity for Year 2 $52,720

Learn more here:.

brainly.com/question/17062268

6 0

3 years ago