Answer:
=25a6−36a4
Step-by-step explanation:
=(5a3+−6a2)(5a3+6a2)
=(5a3)(5a3)+(5a3)(6a2)+(−6a2)(5a3)+(−6a2)(6a2)
=25a6+30a5−30a5−36a4
=25a6−36a4
The answer is: Each bag of flour weighs 1,32 kg.
If we the total weight of the bags is given, and we know both the number of bags of flour and sugar, and we also know the weight of each bag of sugar, then we have to find the unknown, which is X. 30 times X plus 4 times the weight of a bag of sugar would equal 42.6kg. Next step is to put the unknown on one side and the known values on the other side. We have 30 times X equals 42.6 minus 4 times 0.75.
To find X we need to divide the value with 30, or to sum up
30X + 4*0.75 = 42.6
30X + 3 = 42.6
X = (42.6 - 3) / 30
X = 1.32 kg
1/4 2/8 3/12 4/16 5/20 6/24
Given : f(x)= 3|x-2| -5
f(x) is translated 3 units down and 4 units to the left
If any function is translated down then we subtract the units at the end
If any function is translated left then we add the units with x inside the absolute sign
f(x)= 3|x-2| -5
f(x) is translated 3 units down
subtract 3 at the end, so f(x) becomes
f(x)= 3|x-2| -5 -3
f(x) is translated 4 units to the left
Add 4 with x inside the absolute sign, f(x) becomes
f(x)= 3|x-2 + 4| -5 -3
We simplify it and replace f(x) by g(x)
g(x) = 3|x + 2| - 8
a= 3, h = -2 , k = -8