Base=x+7 Height=x Area=60. 60=((x+7)(x))/2----->60=(x^2+7x)/2
120=x^2+7x X^2+7X-120=0. QUDRATIC FORMULA: -7+/- SQRT(49+480)/2
(-7+/-23)/2... 8 and -15. -15 ISNT the answer because you cant have a negative length. X=8 Base=8+7---->15 Height=8
Answer:
B
Step-by-step explanation:
y=x you can imagine by drawing graph
First thing to do is set up your equation:
45/x = 20/100
Cross multiply
4500 = 20x
And divide by 20
Answer: 225 people were surveyed
There are 10,000 total four-digit numbers (1000 through 9999).
Multiples of 2 end in 0, 2, 4, 6, and 8. There are 9*10*10*5 = 4500 four-digit multiples of 2.
Multiples of 5 end in 0 or 5. There are 9*10*10*2 = 1800 four-digit multiples of 5.
There is redundancy between the two sets of numbers, namely those that end in 0, which are both multiples of 2 and 5. There are 9*10*10*1 = 900 four-digit multiples of both 2 and 5.
Then there are 4500 + 1800 - 900 = 5400 total four-digit numbers that are either multiples of 2 or 5, which means the remaining 4600 numbers are neither multiples of 2 nor 5.
6 inches
6 1/14 inches
Since area is defined as length multiplied by width, this is a simple matter of division. I suspect this problem is more a matter of handling fractions, so to make things easier, convert the fractions to improper fractions in order to do the math, then convert to proper fractions after you've gotten the result. Since the area of each rectangle is 12 3/4, multiply 12 by 4 and then add 3 to get 51/4 as the area. Doing the same for the values 2 1/8 and 2 1/10 gives sizes of 17/8 and 21/10 for the widths respectively. So
51/4 / 17/8 = 51/4 * 8/17 = 408/68 = 6/1 = 6
51/4 / 21/10 = 51/4 * 10/21 = 510/84 = 85/14 = 6 1/14
